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leetcode-cn/problem (Chinese)/平均售价 [average-selling-price].html Normal file
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<p>表：<code>Prices</code></p>
<pre>
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| product_id | int |
| start_date | date |
| end_date | date |
| price | int |
+---------------+---------+
(product_id，start_date，end_date) 是 <code>prices</code> 表的主键（具有唯一值的列的组合）。
<code>prices</code> 表的每一行表示的是某个产品在一段时期内的价格。
每个产品的对应时间段是不会重叠的，这也意味着同一个产品的价格时段不会出现交叉。</pre>
<p>&nbsp;</p>
<p>表：<code>UnitsSold</code></p>
<pre>
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| product_id | int |
| purchase_date | date |
| units | int |
+---------------+---------+
<span style="white-space: pre-wrap;">该表可能包含重复数据</span>。
<span style="white-space: pre-wrap;">该</span>表的每一行表示的是每种产品的出售日期，单位和产品 id。</pre>
<p>&nbsp;</p>
<p>编写解决方案以查找每种产品的平均售价。<code>average_price</code> 应该 <strong>四舍五入到小数点后两位</strong>。</p>
<p>返回结果表 <strong>无顺序要求</strong> 。</p>
<p>结果格式如下例所示。</p>
<p>&nbsp;</p>
<p><strong>示例 1：</strong></p>
<pre>
<strong>输入：</strong>
Prices table:
+------------+------------+------------+--------+
| product_id | start_date | end_date | price |
+------------+------------+------------+--------+
| 1 | 2019-02-17 | 2019-02-28 | 5 |
| 1 | 2019-03-01 | 2019-03-22 | 20 |
| 2 | 2019-02-01 | 2019-02-20 | 15 |
| 2 | 2019-02-21 | 2019-03-31 | 30 |
+------------+------------+------------+--------+
UnitsSold table:
+------------+---------------+-------+
| product_id | purchase_date | units |
+------------+---------------+-------+
| 1 | 2019-02-25 | 100 |
| 1 | 2019-03-01 | 15 |
| 2 | 2019-02-10 | 200 |
| 2 | 2019-03-22 | 30 |
+------------+---------------+-------+
<strong>输出：</strong>
+------------+---------------+
| product_id | average_price |
+------------+---------------+
| 1 | 6.96 |
| 2 | 16.96 |
+------------+---------------+
<strong>解释：</strong>
平均售价 = 产品总价 / 销售的产品数量。
产品 1 的平均售价 = ((100 * 5)+(15 * 20) )/ 115 = 6.96
产品 2 的平均售价 = ((200 * 15)+(30 * 30) )/ 230 = 16.96</pre>