mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-09-03 14:32:54 +08:00
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59
leetcode-cn/originData/add-two-promises.json
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59
leetcode-cn/originData/add-two-promises.json
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59
leetcode-cn/originData/calculator-with-method-chaining.json
Normal file
59
leetcode-cn/originData/calculator-with-method-chaining.json
Normal file
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"content": "<p>Design a <code>Calculator</code> class. The class should provide the mathematical operations of addition, subtraction, multiplication, division, and exponentiation. It should also allow consecutive operations to be performed using method chaining. The <code>Calculator</code> class constructor should accept a number which serves as the initial value of <code>result</code>.</p>\n\n<p>Your <font face=\"monospace\"><code>Calculator</code> </font>class should have the following methods:</p>\n\n<ul>\n\t<li><code>add</code> - This method adds the given number <code>value</code> to the <code>result</code> and returns the updated <code>Calculator</code>.</li>\n\t<li><code>subtract</code> - This method subtracts the given number <code>value</code> from the <code>result</code> and returns the updated <code>Calculator</code>.</li>\n\t<li><code>multiply</code> - This method multiplies the <code>result</code> by the given number <code>value</code> and returns the updated <code>Calculator</code>.</li>\n\t<li><code>divide</code> - This method divides the <code>result</code> by the given number <code>value</code> and returns the updated <code>Calculator</code>. If the passed value is <code>0</code>, an error <code>"Division by zero is not allowed"</code> should be thrown.</li>\n\t<li><code>power</code> - This method raises the <code>result</code> to the power of the given number <code>value</code> and returns the updated <code>Calculator</code>.</li>\n\t<li><code>getResult</code> - This method returns the <code>result</code>.</li>\n</ul>\n\n<p>Solutions within <code>10<sup>-5</sup></code> of the actual result are considered correct.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> actions = ["Calculator", "add", "subtract", "getResult"], values = [10, 5, 7]\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> \nnew Calculator(10).add(5).subtract(7).getResult() // 10 + 5 - 7 = 8\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> actions = ["Calculator", "multiply", "power", "getResult"], values = [2, 5, 2]\n<strong>Output:</strong> 100\n<strong>Explanation:</strong> \nnew Calculator(2).multiply(5).power(2).getResult() // (2 * 5) ^ 2 = 100\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> actions = ["Calculator", "divide", "getResult"], values = [20, 0]\n<strong>Output:</strong> "Division by zero is not allowed"\n<strong>Explanation:</strong> \nnew Calculator(20).divide(0).getResult() // 20 / 0 \n\nThe error should be thrown because we cannot divide by zero.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= actions.length <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>1 <= values.length <= 2 * 10<sup>4</sup></code><code> - 1</code></li>\n\t<li><code>actions[i] is one of "Calculator", "add", "subtract", "multiply", "divide", "power", and "getResult"</code></li>\n\t<li><code><font face=\"monospace\">Last action is always "getResult"</font></code></li>\n\t<li><code><font face=\"monospace\">values is a JSON array of numbers</font></code></li>\n</ul>\n",
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"content": "<p>Given an array of asynchronous functions <code>functions</code>, return a new promise <code>promise</code>. Each function in the array accepts no arguments and returns a promise.</p>\n\n<p><code>promise</code> resolves:</p>\n\n<ul>\n\t<li>When all the promises returned from <code>functions</code> were resolved successfully. The resolved value of <code>promise</code> should be an array of all the resolved values of promises in the same order as they were in the <code>functions.</code></li>\n</ul>\n\n<p><code>promise</code> rejects:</p>\n\n<ul>\n\t<li>When any of the promises returned from <code>functions</code> were rejected. <code>promise</code> should also reject with the reason of the first rejection.</li>\n</ul>\n\n<p>Please solve it without using the built-in <code>Promise.all</code> function.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n () => new Promise(resolve => setTimeout(() => resolve(5), 200))\n]\n<strong>Output:</strong> {"t": 200, "resolved": [5]}\n<strong>Explanation:</strong> \npromiseAll(functions).then(console.log); // [5]\n\nThe single function was resolved at 200ms with a value of 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n () => new Promise(resolve => setTimeout(() => resolve(1), 200)), \n () => new Promise((resolve, reject) => setTimeout(() => reject("Error"), 100))\n]\n<strong>Output:</strong> {"t": 100, "rejected": "Error"}\n<strong>Explanation:</strong> Since one of the promises rejected, the returned promise also rejected with the same error at the same time.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n () => new Promise(resolve => setTimeout(() => resolve(4), 50)), \n () => new Promise(resolve => setTimeout(() => resolve(10), 150)), \n () => new Promise(resolve => setTimeout(() => resolve(16), 100))\n]\n<strong>Output:</strong> {"t": 150, "resolved": [4, 10, 16]}\n<strong>Explanation:</strong> All the promises resolved with a value. The returned promise resolved when the last promise resolved.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>functions is an array of functions that returns promises</code></li>\n\t<li><code>1 <= functions.length <= 10</code></li>\n</ul>\n",
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165
leetcode-cn/originData/find-a-good-subset-of-the-matrix.json
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165
leetcode-cn/originData/find-a-good-subset-of-the-matrix.json
Normal file
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File diff suppressed because one or more lines are too long
59
leetcode-cn/originData/interval-cancellation.json
Normal file
59
leetcode-cn/originData/interval-cancellation.json
Normal file
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"content": "Given a function <code>fn,</code> an array of arguments <code>args</code>, and an interval time <code>t</code>, return a cancel function <code>cancelFn</code>. The function <code>fn</code> should be called with <code>args</code> immediately and then called again every <code>t</code> milliseconds until <code>cancelFn</code> is called.\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x) => x * 2, args = [4], t = 20, cancelT = 110\n<strong>Output:</strong> \n[\n {"time": 0, "returned": 8},\n {"time": 20, "returned": 8},\n {"time": 40, "returned": 8},\n {"time": 60, "returned": 8},\n {"time": 80, "returned": 8},\n {"time": 100, "returned": 8}\n]\n<strong>Explanation:</strong> Every 20ms, fn(4) is called. Until t=110ms, then it is cancelled.\n\nconst cancel = cancellable(x => x * 2, [4], 20);\nsetTimeout(cancel, 110);\n\n1st fn call is at 0ms. fn(4) returns 8.\n2nd fn call is at 20ms. fn(4) returns 8.\n3rd fn call is at 40ms. fn(4) returns 8.\n4th fn call is at 60ms. fn(4) returns 8.\n5th fn call is at 80ms. fn(4) returns 8.\n6th fn call is at 100ms. fn(4) returns 8.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x1, x2) => (x1 * x2), args = [2, 5], t = 25, cancelT = 140\n<strong>Output:</strong> \n[\n {"time": 0, "returned": 10},\n {"time": 25, "returned": 10},\n {"time": 50, "returned": 10},\n {"time": 75, "returned": 10},\n {"time": 100, "returned": 10},\n {"time": 125, "returned": 10}\n]\n<strong>Explanation:</strong> Every 25ms, fn(2, 5) is called. Until t=140ms, then it is cancelled.\n1st fn call is at 0ms \n2nd fn call is at 25ms \n3rd fn call is at 50ms \n4th fn call is at 75ms \n5th fn call is at 100ms \n6th fn call is at 125ms\nCancelled at 140ms\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x1, x2, x3) => (x1 + x2 + x3), args = [5, 1, 3], t = 50, cancelT = 180\n<strong>Output:</strong> \n[\n {"time": 0, "returned": 9},\n {"time": 50, "returned": 9},\n {"time": 100, "returned": 9},\n {"time": 150, "returned": 9}\n]\n<strong>Explanation:</strong> Every 50ms, fn(5, 1, 3) is called. Until t=180ms, then it is cancelled. \n1st fn call is at 0ms\n2nd fn call is at 50ms\n3rd fn call is at 100ms\n4th fn call is at 150ms\nCancelled at 180ms\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>fn is a function</code></li>\n\t<li><code>args is a valid JSON array</code></li>\n\t<li><code>1 <= args.length <= 10</code></li>\n\t<li><code><font face=\"monospace\">20 <= t <= 1000</font></code></li>\n\t<li><code><font face=\"monospace\">10 <= cancelT <= 1000</font></code></li>\n</ul>\n",
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||||
"translatedTitle": "间隔取消",
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||||
"translatedContent": "现给定一个函数 <code>fn</code>，一个参数数组 <code>args</code> 和一个时间间隔 <code>t</code>，返回一个取消函数 <code>cancelFn</code>。函数 <code>fn</code> 应该立即使用 <code>args</code> 调用，并且在每个 <code>t</code> 毫秒内再次调用，直到调用 <code>cancelFn</code>。\n<p> </p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x) => x * 2, args = [4], t = 20, cancelT = 110\n<b>输出：</b>\n[\n {\"time\": 0, \"returned\": 8},\n {\"time\": 20, \"returned\": 8},\n {\"time\": 40, \"returned\": 8},\n {\"time\": 60, \"returned\": 8},\n {\"time\": 80, \"returned\": 8},\n {\"time\": 100, \"returned\": 8}\n]\n<strong>解释：</strong> 每隔 20ms，调用 fn(4)。直到 t=110ms，然后取消。\nconst cancel = cancellable(x => x * 2, [4], 20);\nsetTimeout(cancel, 110);\n第一次调用 fn 是在 0ms。fn(4) 返回 8。\n第二次调用 fn 是在 20ms。fn(4) 返回 8。\n第三次调用 fn 是在 40ms。fn(4) 返回 8。\n第四次调用 fn 是在 60ms。fn(4) 返回 8。\n第五次调用 fn 是在 80ms。fn(4) 返回 8。\n第六次调用 fn 是在 100ms。fn(4) 返回 8。</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x1, x2) => (x1 * x2), args = [2, 5], t = 25, cancelT = 140\n<strong>输出：</strong> \n[\n {\"time\": 0, \"returned\": 10},\n {\"time\": 25, \"returned\": 10},\n {\"time\": 50, \"returned\": 10},\n {\"time\": 75, \"returned\": 10},\n {\"time\": 100, \"returned\": 10},\n {\"time\": 125, \"returned\": 10}\n]\n<strong>解释：</strong>每隔 25ms，调用 fn(2, 5)。直到 t=140ms，然后取消。\n第一次调用 fn 是在 0ms\n第二次调用 fn 是在 25ms\n第三次调用 fn 是在 50ms\n第四次调用 fn 是在 75ms\n第五次调用 fn 是在 100ms\n第六次调用 fn 是在 125ms\n在 140ms 取消\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x1, x2, x3) => (x1 + x2 + x3), args = [5, 1, 3], t = 50, cancelT = 180\n<b>输出：</b>\n[\n {\"time\": 0, \"returned\": 9},\n {\"time\": 50, \"returned\": 9},\n {\"time\": 100, \"returned\": 9},\n {\"time\": 150, \"returned\": 9}\n]\n<b>解释：</b>每隔 50ms，调用 fn(5, 1, 3)。直到 t=180ms，然后取消。\n第一次调用 fn 是在 0ms\n第二次调用 fn 是在 50ms\n第三次调用 fn 是在 100ms\n第四次调用 fn 是在 150ms\n在 180ms 取消\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>fn 是一个函数</code></li>\n\t<li><code>args 是一个有效的 JSON 数组</code></li>\n\t<li><code>1 <= args.length <= 10</code></li>\n\t<li><code><font face=\"monospace\">20 <= t <= 1000</font></code></li>\n\t<li><code><font face=\"monospace\">10 <= cancelT <= 1000</font></code></li>\n</ul>\n",
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59
leetcode-cn/originData/is-object-empty.json
Normal file
59
leetcode-cn/originData/is-object-empty.json
Normal file
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|
||||
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59
leetcode-cn/originData/join-two-arrays-by-id.json
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"content": "<p>Given two arrays <code>arr1</code> and <code>arr2</code>, return a new array <code>joinedArray</code>. All the objects in each of the two inputs arrays will contain an <code>id</code> field that has an integer value. <code>joinedArray</code> is an array formed by merging <code>arr1</code> and <code>arr2</code> based on their <code>id</code> key. The length of <code>joinedArray</code> should be the length of unique values of <code>id</code>. The returned array should be sorted in <strong>ascending</strong> order based on the <code>id</code> key.</p>\n\n<p>If a given <code>id</code> exists in one array but not the other, the single object with that <code>id</code> should be included in the result array without modification.</p>\n\n<p>If two objects share an <code>id</code>, their properties should be merged into a single object:</p>\n\n<ul>\n\t<li>If a key only exists in one object, that single key-value pair should be included in the object.</li>\n\t<li>If a key is included in both objects, the value in the object from <code>arr2</code> should override the value from <code>arr1</code>.</li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \narr1 = [\n {"id": 1, "x": 1},\n {"id": 2, "x": 9}\n], \narr2 = [\n {"id": 3, "x": 5}\n]\n<strong>Output:</strong> \n[\n {"id": 1, "x": 1},\n {"id": 2, "x": 9},\n {"id": 3, "x": 5}\n]\n<strong>Explanation:</strong> There are no duplicate ids so arr1 is simply concatenated with arr2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> \narr1 = [\n {"id": 1, "x": 2, "y": 3},\n {"id": 2, "x": 3, "y": 6}\n], \narr2 = [\n {"id": 2, "x": 10, "y": 20},\n {"id": 3, "x": 0, "y": 0}\n]\n<strong>Output:</strong> \n[\n {"id": 1, "x": 2, "y": 3},\n {"id": 2, "x": 10, "y": 20},\n {"id": 3, "x": 0, "y": 0}\n]\n<strong>Explanation:</strong> The two objects with id=1 and id=3 are included in the result array without modifiction. The two objects with id=2 are merged together. The keys from arr2 override the values in arr1.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> \narr1 = [\n {"id": 1, "b": {"b": 94},"v": [4, 3], "y": 48}\n]\narr2 = [\n {"id": 1, "b": {"c": 84}, "v": [1, 3]}\n]\n<strong>Output:</strong> [\n {"id": 1, "b": {"c": 84}, "v": [1, 3], "y": 48}\n]\n<strong>Explanation:</strong> The two objects with id=1 are merged together. For the keys "b" and "v" the values from arr2 are used. Since the key "y" only exists in arr1, that value is taken form arr1.</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>arr1 and arr2 are valid JSON arrays</code></li>\n\t<li><code>Each object in arr1 and arr2 has a unique integer id key</code></li>\n\t<li><code>2 <= JSON.stringify(arr1).length <= 10<sup>6</sup></code></li>\n\t<li><code>2 <= JSON.stringify(arr2).length <= 10<sup>6</sup></code></li>\n</ul>\n",
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"translatedContent": "<p>现给定两个数组 <code>arr1</code> 和 <code>arr2</code> ，返回一个新的数组 <code>joinedArray</code> 。两个输入数组中的每个对象都包含一个 <code>id</code> 字段。<code>joinedArray</code> 是一个通过 <code>id</code> 将 <code>arr1</code> 和 <code>arr2</code> 连接而成的数组。<code>joinedArray</code> 的长度应为唯一值 <code>id</code> 的长度。返回的数组应按 <code>id</code> <strong>升序</strong> 排序。</p>\n\n<p>如果一个 <code>id</code> 存在于一个数组中但不存在于另一个数组中，则该对象应包含在结果数组中且不进行修改。</p>\n\n<p>如果两个对象共享一个 <code>id</code> ，则它们的属性应进行合并：</p>\n\n<ul>\n\t<li>如果一个键只存在于一个对象中，则该键值对应该包含在对象中。</li>\n\t<li>如果一个键在两个对象中都包含，则 <code>arr2</code> 中的值应覆盖 <code>arr1</code> 中的值。</li>\n</ul>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>\narr1 = [\n {\"id\": 1, \"x\": 1},\n {\"id\": 2, \"x\": 9}\n], \narr2 = [\n {\"id\": 3, \"x\": 5}\n]\n<b>输出：</b>\n[\n {\"id\": 1, \"x\": 1},\n {\"id\": 2, \"x\": 9},\n {\"id\": 3, \"x\": 5}\n]\n<b>解释：</b>没有共同的 id，因此将 arr1 与 arr2 简单地连接起来。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>\narr1 = [\n {\"id\": 1, \"x\": 2, \"y\": 3},\n {\"id\": 2, \"x\": 3, \"y\": 6}\n], \narr2 = [\n {\"id\": 2, \"x\": 10, \"y\": 20},\n {\"id\": 3, \"x\": 0, \"y\": 0}\n]\n<b>输出：</b>\n[\n {\"id\": 1, \"x\": 2, \"y\": 3},\n {\"id\": 2, \"x\": 10, \"y\": 20},\n {\"id\": 3, \"x\": 0, \"y\": 0}\n]\n<b>解释：</b>id 为 1 和 id 为 3 的对象在结果数组中保持不变。id 为 2 的两个对象合并在一起。arr2 中的键覆盖 arr1 中的值。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>\narr1 = [\n {\"id\": 1, \"b\": {\"b\": 94},\"v\": [4, 3], \"y\": 48}\n]\narr2 = [\n {\"id\": 1, \"b\": {\"c\": 84}, \"v\": [1, 3]}\n]\n<strong>输出：</strong> [\n {\"id\": 1, \"b\": {\"c\": 84}, \"v\": [1, 3], \"y\": 48}\n]\n<b>解释：</b>具有 id 为 1 的对象合并在一起。对于键 \"b\" 和 \"v\" ，使用 arr2 中的值。由于键 \"y\" 只存在于 arr1 中，因此取 arr1 的值。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>arr1 和 arr2 都是有效的 JSON 数组</code></li>\n\t<li><code>在 arr1 和 arr2 中都有唯一的键值 id</code></li>\n\t<li><code>2 <= JSON.stringify(arr1).length <= 10<sup>6</sup></code></li>\n\t<li><code>2 <= JSON.stringify(arr2).length <= 10<sup>6</sup></code></li>\n</ul>\n",
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leetcode-cn/originData/maximum-sum-queries.json
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leetcode-cn/originData/sort-by.json
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178
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178
leetcode-cn/originData/sum-of-matrix-after-queries.json
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Reference in New Issue
Block a user