mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-09-05 23:41:41 +08:00
update
This commit is contained in:
zhangbk1
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178
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leetcode-cn/originData/alternating-groups-iii.json
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leetcode-cn/originData/design-neighbor-sum-service.json
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leetcode-cn/originData/find-if-digit-game-can-be-won.json
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leetcode-cn/originData/find-the-winning-player-in-coin-game.json
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leetcode-cn/originData/maximum-score-from-grid-operations.json
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leetcode-cn/originData/odd-and-even-transactions.json
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leetcode-cn/originData/odd-and-even-transactions.json
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"content": "<p>Table: <code>transactions</code></p>\n\n<pre>\n+------------------+------+\n| Column Name | Type | \n+------------------+------+\n| transaction_id | int |\n| amount | int |\n| transaction_date | date |\n+------------------+------+\nThe transactions_id column uniquely identifies each row in this table.\nEach row of this table contains the transaction id, amount and transaction date.\n</pre>\n\n<p>Write a solution to find the <strong>sum of amounts</strong> for <strong>odd</strong> and <strong>even</strong> transactions for each day. If there are no odd or even transactions for a specific date, display as <code>0</code>.</p>\n\n<p>Return <em>the result table ordered by</em> <code>transaction_date</code> <em>in <strong>ascending</strong> order</em>.</p>\n\n<p>The result format is in the following example.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong></p>\n\n<p><code>transactions</code> table:</p>\n\n<pre class=\"example-io\">\n+----------------+--------+------------------+\n| transaction_id | amount | transaction_date |\n+----------------+--------+------------------+\n| 1 | 150 | 2024-07-01 |\n| 2 | 200 | 2024-07-01 |\n| 3 | 75 | 2024-07-01 |\n| 4 | 300 | 2024-07-02 |\n| 5 | 50 | 2024-07-02 |\n| 6 | 120 | 2024-07-03 |\n+----------------+--------+------------------+\n </pre>\n\n<p><strong>Output:</strong></p>\n\n<pre class=\"example-io\">\n+------------------+---------+----------+\n| transaction_date | odd_sum | even_sum |\n+------------------+---------+----------+\n| 2024-07-01 | 75 | 350 |\n| 2024-07-02 | 0 | 350 |\n| 2024-07-03 | 0 | 120 |\n+------------------+---------+----------+\n </pre>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>For transaction dates:\n\t<ul>\n\t\t<li>2024-07-01:\n\t\t<ul>\n\t\t\t<li>Sum of amounts for odd transactions: 75</li>\n\t\t\t<li>Sum of amounts for even transactions: 150 + 200 = 350</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>2024-07-02:\n\t\t<ul>\n\t\t\t<li>Sum of amounts for odd transactions: 0</li>\n\t\t\t<li>Sum of amounts for even transactions: 300 + 50 = 350</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>2024-07-03:\n\t\t<ul>\n\t\t\t<li>Sum of amounts for odd transactions: 0</li>\n\t\t\t<li>Sum of amounts for even transactions: 120</li>\n\t\t</ul>\n\t\t</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p><strong>Note:</strong> The output table is ordered by <code>transaction_date</code> in ascending order.</p>\n</div>\n",
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"translatedTitle": "奇数和偶数交易",
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"translatedContent": "<p>表：<code>transactions</code></p>\n\n<pre>\n+------------------+------+\n| Column Name | Type | \n+------------------+------+\n| transaction_id | int |\n| amount | int |\n| transaction_date | date |\n+------------------+------+\ntransactions_id 列唯一标识了表中的每一行。\n这张表的每一行包含交易 id，金额总和和交易日期。\n</pre>\n\n<p>编写一个解决方案来查找每天 <strong>奇数</strong> 交易金额和 <strong>偶数</strong> 交易金额的 <strong>总和</strong>。如果某天没有奇数或偶数交易，显示为 <code>0</code>。</p>\n\n<p>返回结果表以 <code>transaction_date</code> <strong>升序</strong> 排序。</p>\n\n<p>结果格式如下所示。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例：</strong></p>\n\n<div class=\"example-block\">\n<p><b>输入：</b></p>\n\n<p><code>transactions</code> 表：</p>\n\n<pre class=\"example-io\">\n+----------------+--------+------------------+\n| transaction_id | amount | transaction_date |\n+----------------+--------+------------------+\n| 1 | 150 | 2024-07-01 |\n| 2 | 200 | 2024-07-01 |\n| 3 | 75 | 2024-07-01 |\n| 4 | 300 | 2024-07-02 |\n| 5 | 50 | 2024-07-02 |\n| 6 | 120 | 2024-07-03 |\n+----------------+--------+------------------+\n </pre>\n\n<p><strong>输出：</strong></p>\n\n<pre class=\"example-io\">\n+------------------+---------+----------+\n| transaction_date | odd_sum | even_sum |\n+------------------+---------+----------+\n| 2024-07-01 | 75 | 350 |\n| 2024-07-02 | 0 | 350 |\n| 2024-07-03 | 0 | 120 |\n+------------------+---------+----------+\n </pre>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>对于交易日期：\n\t<ul>\n\t\t<li>2024-07-01:\n\t\t<ul>\n\t\t\t<li>奇数交易金额总和：75</li>\n\t\t\t<li>偶数交易金额总和：150 + 200 = 350</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>2024-07-02:\n\t\t<ul>\n\t\t\t<li>奇数交易金额总和：0</li>\n\t\t\t<li>偶数交易金额总和：300 + 50 = 350</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>2024-07-03:\n\t\t<ul>\n\t\t\t<li>奇数交易金额总和：0</li>\n\t\t\t<li>偶数交易金额总和：120</li>\n\t\t</ul>\n\t\t</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p><b>注意：</b>输出表以 <code>transaction_date</code> 升序排序。</p>\n</div>\n",
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Reference in New Issue
Block a user