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leetcode/problem/odd-and-even-transactions.html
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leetcode/problem/odd-and-even-transactions.html
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<p>Table: <code>transactions</code></p>
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<pre>
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+------------------+------+
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| Column Name | Type |
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+------------------+------+
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| transaction_id | int |
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| amount | int |
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| transaction_date | date |
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+------------------+------+
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The transactions_id column uniquely identifies each row in this table.
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Each row of this table contains the transaction id, amount and transaction date.
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</pre>
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<p>Write a solution to find the <strong>sum of amounts</strong> for <strong>odd</strong> and <strong>even</strong> transactions for each day. If there are no odd or even transactions for a specific date, display as <code>0</code>.</p>
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<p>Return <em>the result table ordered by</em> <code>transaction_date</code> <em>in <strong>ascending</strong> order</em>.</p>
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<p>The result format is in the following example.</p>
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<p> </p>
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<p><strong class="example">Example:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong></p>
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<p><code>transactions</code> table:</p>
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<pre class="example-io">
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+----------------+--------+------------------+
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| transaction_id | amount | transaction_date |
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+----------------+--------+------------------+
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| 1 | 150 | 2024-07-01 |
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| 2 | 200 | 2024-07-01 |
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| 3 | 75 | 2024-07-01 |
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| 4 | 300 | 2024-07-02 |
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| 5 | 50 | 2024-07-02 |
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| 6 | 120 | 2024-07-03 |
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+----------------+--------+------------------+
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</pre>
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<p><strong>Output:</strong></p>
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<pre class="example-io">
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+------------------+---------+----------+
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| transaction_date | odd_sum | even_sum |
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+------------------+---------+----------+
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| 2024-07-01 | 75 | 350 |
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| 2024-07-02 | 0 | 350 |
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| 2024-07-03 | 0 | 120 |
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+------------------+---------+----------+
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</pre>
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<p><strong>Explanation:</strong></p>
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<ul>
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<li>For transaction dates:
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<ul>
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<li>2024-07-01:
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<ul>
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<li>Sum of amounts for odd transactions: 75</li>
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<li>Sum of amounts for even transactions: 150 + 200 = 350</li>
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</ul>
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</li>
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<li>2024-07-02:
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<ul>
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<li>Sum of amounts for odd transactions: 0</li>
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<li>Sum of amounts for even transactions: 300 + 50 = 350</li>
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</ul>
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</li>
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<li>2024-07-03:
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<ul>
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<li>Sum of amounts for odd transactions: 0</li>
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<li>Sum of amounts for even transactions: 120</li>
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</ul>
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</li>
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</ul>
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</li>
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</ul>
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<p><strong>Note:</strong> The output table is ordered by <code>transaction_date</code> in ascending order.</p>
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</div>
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