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leetcode-cn/problem (English)/最小处理时间(English) [minimum-processing-time].html
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<p>You have <code>n</code> processors each having <code>4</code> cores and <code>n * 4</code> tasks that need to be executed such that each core should perform only <strong>one</strong> task.</p>
<p>You have a certain number of processors, each having 4 cores. The number of tasks to be executed is four times the number of processors. Each task must be assigned to a unique core, and each core can only be used once.</p>
<p>Given a <strong>0-indexed</strong> integer array <code>processorTime</code> representing the time at which each processor becomes available for the first time and a <strong>0-indexed </strong>integer array <code>tasks</code> representing the time it takes to execute each task, return <em>the <strong>minimum</strong> time when all of the tasks have been executed by the processors.</em></p>
<p><strong>Note: </strong>Each core executes the task independently of the others.</p>
<p>You are given an array <code>processorTime</code> representing the time each processor becomes available and an array <code>tasks</code> representing how long each task takes to complete. Return the&nbsp;<em>minimum</em> time needed to complete all tasks.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> processorTime = [8,10], tasks = [2,2,3,1,8,7,4,5]
<strong>Output:</strong> 16
<strong>Explanation:</strong>
It&#39;s optimal to assign the tasks at indexes 4, 5, 6, 7 to the first processor which becomes available at time = 8, and the tasks at indexes 0, 1, 2, 3 to the second processor which becomes available at time = 10.
Time taken by the first processor to finish execution of all tasks = max(8 + 8, 8 + 7, 8 + 4, 8 + 5) = 16.
Time taken by the second processor to finish execution of all tasks = max(10 + 2, 10 + 2, 10 + 3, 10 + 1) = 13.
Hence, it can be shown that the minimum time taken to execute all the tasks is 16.</pre>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">processorTime = [8,10], tasks = [2,2,3,1,8,7,4,5]</span></p>
<p><strong>Output:</strong> <span class="example-io">16</span></p>
<p><strong>Explanation:</strong></p>
<p>Assign the tasks at indices 4, 5, 6, 7 to the first processor which becomes available at <code>time = 8</code>, and the tasks at indices 0, 1, 2, 3 to the second processor which becomes available at <code>time = 10</code>.&nbsp;</p>
<p>The time taken by the first processor to finish the execution of all tasks is&nbsp;<code>max(8 + 8, 8 + 7, 8 + 4, 8 + 5) = 16</code>.</p>
<p>The time taken by the second processor to finish the execution of all tasks is&nbsp;<code>max(10 + 2, 10 + 2, 10 + 3, 10 + 1) = 13</code>.</p>
</div>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> processorTime = [10,20], tasks = [2,3,1,2,5,8,4,3]
<strong>Output:</strong> 23
<strong>Explanation:</strong>
It&#39;s optimal to assign the tasks at indexes 1, 4, 5, 6 to the first processor which becomes available at time = 10, and the tasks at indexes 0, 2, 3, 7 to the second processor which becomes available at time = 20.
Time taken by the first processor to finish execution of all tasks = max(10 + 3, 10 + 5, 10 + 8, 10 + 4) = 18.
Time taken by the second processor to finish execution of all tasks = max(20 + 2, 20 + 1, 20 + 2, 20 + 3) = 23.
Hence, it can be shown that the minimum time taken to execute all the tasks is 23.
</pre>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">processorTime = [10,20], tasks = [2,3,1,2,5,8,4,3]</span></p>
<p><strong>Output:</strong> <span class="example-io">23</span></p>
<p><strong>Explanation:</strong></p>
<p>Assign the tasks at indices 1, 4, 5, 6 to the first processor and the others to the second processor.</p>
<p>The time taken by the first processor to finish the execution of all tasks is <code>max(10 + 3, 10 + 5, 10 + 8, 10 + 4) = 18</code>.</p>
<p>The time taken by the second processor to finish the execution of all tasks is <code>max(20 + 2, 20 + 1, 20 + 2, 20 + 3) = 23</code>.</p>
</div>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>