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leetcode-cn/problem (English)/将所有数字用字符替换(English) [replace-all-digits-with-characters].html
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<p>You are given a <strong>0-indexed</strong> string <code>s</code> that has lowercase English letters in its <strong>even</strong> indices and digits in its <strong>odd</strong> indices.</p>
<p>There is a function <code>shift(c, x)</code>, where <code>c</code> is a character and <code>x</code> is a digit, that returns the <code>x<sup>th</sup></code> character after <code>c</code>.</p>
<p>You must perform an operation <code>shift(c, x)</code>, where <code>c</code> is a character and <code>x</code> is a digit, that returns the <code>x<sup>th</sup></code> character after <code>c</code>.</p>
<ul>
<li>For example, <code>shift(&#39;a&#39;, 5) = &#39;f&#39;</code> and <code>shift(&#39;x&#39;, 0) = &#39;x&#39;</code>.</li>
</ul>
<p>For every <strong>odd</strong>&nbsp;index <code>i</code>, you want to replace the digit <code>s[i]</code> with <code>shift(s[i-1], s[i])</code>.</p>
<p>For every <strong>odd</strong> index <code>i</code>, you want to replace the digit <code>s[i]</code> with the result of the <code>shift(s[i-1], s[i])</code> operation.</p>
<p>Return <code>s</code><em> after replacing all digits. It is <strong>guaranteed</strong> that </em><code>shift(s[i-1], s[i])</code><em> will never exceed </em><code>&#39;z&#39;</code>.</p>
<p>Return <code>s</code><em> </em>after replacing all digits. It is <strong>guaranteed</strong> that<em> </em><code>shift(s[i-1], s[i])</code><em> </em>will never exceed<em> </em><code>&#39;z&#39;</code>.</p>
<p><strong>Note</strong> that <code>shift(c, x)</code> is <strong>not</strong> a preloaded function, but an operation <em>to be implemented</em> as part of the solution.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>