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leetcode-cn/problem (English)/字符串中的第一个唯一字符(English) [first-unique-character-in-a-string].html
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<p>Given a string <code>s</code>, <em>find the first non-repeating character in it and return its index</em>. If it does not exist, return <code>-1</code>.</p>
<p>Given a string <code>s</code>, find the <strong>first</strong> non-repeating character in it and return its index. If it <strong>does not</strong> exist, return <code>-1</code>.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> s = "leetcode"
<strong>Output:</strong> 0
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> s = "loveleetcode"
<strong>Output:</strong> 2
</pre><p><strong class="example">Example 3:</strong></p>
<pre><strong>Input:</strong> s = "aabb"
<strong>Output:</strong> -1
</pre>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;leetcode&quot;</span></p>
<p><strong>Output:</strong> <span class="example-io">0</span></p>
<p><strong>Explanation:</strong></p>
<p>The character <code>&#39;l&#39;</code> at index 0 is the first character that does not occur at any other index.</p>
</div>
<p><strong class="example">Example 2:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;loveleetcode&quot;</span></p>
<p><strong>Output:</strong> <span class="example-io">2</span></p>
</div>
<p><strong class="example">Example 3:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;aabb&quot;</span></p>
<p><strong>Output:</strong> <span class="example-io">-1</span></p>
</div>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>