coder-xiaomo/leetcode-problemset
1
0
Fork 0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-09-12 02:41:42 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee

批量更新数据

Browse Source
This commit is contained in:
小墨
2025-01-09 20:29:41 +08:00
parent 04ecea043d
commit 48cdd06c2b
5053 changed files with 156164 additions and 135322 deletions
Download Patch File Download Diff File Expand all files Collapse all files

8
leetcode-cn/problem (Chinese)/子数组按位或操作 [bitwise-ors-of-subarrays].html
View File

@@ -1,8 +1,8 @@
<p>我们有一个非负整数数组<meta charset="UTF-8" />&nbsp;<code>arr</code>&nbsp;。</p>
<p>给定一个整数数组<meta charset="UTF-8" />&nbsp;<code>arr</code>，返回所有&nbsp;<code>arr</code>&nbsp;的非空子数组的不同按位或的数量。</p>
<p>对于每个（连续的）子数组<meta charset="UTF-8" />&nbsp;<code>sub = [arr[i], arr[i + 1], ..., arr[j]]</code>&nbsp;（&nbsp;<code>i &lt;= j</code>），我们对<meta charset="UTF-8" />&nbsp;<code>sub</code>&nbsp;中的每个元素进行按位或操作，获得结果<meta charset="UTF-8" />&nbsp;<code>arr[i] | arr[i + 1] | ... | arr[j]</code>&nbsp;。</p>
<p>子数组的按位或是子数组中每个整数的按位或。含有一个整数的子数组的按位或就是该整数。</p>
<p>返回可能结果的数量。 多次出现的结果在最终答案中仅计算一次。</p>
<p><strong>子数组</strong> 是数组内连续的非空元素序列。</p>
<p>&nbsp;</p>
@@ -41,5 +41,5 @@
<ul>
<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>4</sup></code></li>
<li><code>0 &lt;= nums[i]&nbsp;&lt;= 10<sup>9</sup></code>​​​​​​​</li>
<li><code>0 &lt;= nums[i]&nbsp;&lt;= 10<sup>9</sup></code></li>
</ul>