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2025-01-09 20:29:41 +08:00
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leetcode-cn/problem (Chinese)/反转每对括号间的子串 [reverse-substrings-between-each-pair-of-parentheses].html
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<strong>输出：</strong>"leetcode"
<strong>解释：</strong>先反转子字符串 "oc" ，接着反转 "etco" ，然后反转整个字符串。</pre>
<p><strong>示例 4：</strong></p>
<pre>
<strong>输入：</strong>s = "a(bcdefghijkl(mno)p)q"
<strong>输出：</strong>"apmnolkjihgfedcbq"
</pre>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>