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https://gitee.com/coder-xiaomo/leetcode-problemset
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批量更新数据
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@@ -12,12 +12,12 @@
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"translatedContent": "<p>表：<code>Employee</code></p>\n\n<pre>\n+---------------+---------+\n| Column Name | Type |\n+---------------+---------+\n| employee_id | int |\n| department_id | int |\n| primary_flag | varchar |\n+---------------+---------+\n这张表的主键为 employee_id, department_id (具有唯一值的列的组合)\nemployee_id 是员工的ID\ndepartment_id 是部门的ID，表示员工与该部门有关系\nprimary_flag 是一个枚举类型，值分别为('Y', 'N'). 如果值为'Y',表示该部门是员工的直属部门。 如果值是'N',则否\n</pre>\n\n<p> </p>\n\n<p>一个员工可以属于多个部门。当一个员工加入<strong>超过一个部门</strong>的时候，他需要决定哪个部门是他的直属部门。请注意，当员工只加入一个部门的时候，那这个部门将默认为他的直属部门，虽然表记录的值为<code>'N'</code>.</p>\n\n<p>请编写解决方案，查出员工所属的直属部门。</p>\n\n<p>返回结果 <strong>没有顺序要求</strong> 。</p>\n\n<p>返回结果格式如下例子所示：</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>\nEmployee table:\n+-------------+---------------+--------------+\n| employee_id | department_id | primary_flag |\n+-------------+---------------+--------------+\n| 1 | 1 | N |\n| 2 | 1 | Y |\n| 2 | 2 | N |\n| 3 | 3 | N |\n| 4 | 2 | N |\n| 4 | 3 | Y |\n| 4 | 4 | N |\n+-------------+---------------+--------------+\n<strong>输出：</strong>\n+-------------+---------------+\n| employee_id | department_id |\n+-------------+---------------+\n| 1 | 1 |\n| 2 | 1 |\n| 3 | 3 |\n| 4 | 3 |\n+-------------+---------------+\n<strong>解释：</strong>\n- 员工 1 的直属部门是 1\n- 员工 2 的直属部门是 1\n- 员工 3 的直属部门是 3\n- 员工 4 的直属部门是 3</pre>\n\n<p> </p>\n",
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@@ -79,7 +79,7 @@
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"insert into Employee (employee_id, department_id, primary_flag) values ('4', '4', 'N')"
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