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https://gitee.com/coder-xiaomo/leetcode-problemset
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@@ -12,12 +12,12 @@
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"translatedContent": "<p>请你编写一个生成器函数，并返回一个可以生成 <strong>斐波那契数列</strong> 的生成器对象。</p>\n\n<p><strong>斐波那契数列</strong> 的递推公式为 <code>X<sub>n</sub> = X<sub>n-1</sub> + X<sub>n-2</sub></code> 。</p>\n\n<p>这个数列的前几个数字是 <code>0, 1, 1, 2, 3, 5, 8, 13</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>callCount = 5\n<b>输出：</b>[0,1,1,2,3]\n<strong>解释：</strong>\nconst gen = fibGenerator();\ngen.next().value; // 0\ngen.next().value; // 1\ngen.next().value; // 1\ngen.next().value; // 2\ngen.next().value; // 3\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>callCount = 0\n<strong>输出：</strong>[]\n<b>解释：</b>gen.next() 永远不会被调用，所以什么也不会输出\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= callCount <= 50</code></li>\n</ul>\n",
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"code": "function* fibGenerator(): Generator<number, any, number> {\n\t\n};\n\n/**\n * const gen = fibGenerator();\n * gen.next().value; // 0\n * gen.next().value; // 1\n */",
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"code": "function* fibGenerator(): Generator<number, any, number> {\n \n};\n\n/**\n * const gen = fibGenerator();\n * gen.next().value; // 0\n * gen.next().value; // 1\n */",
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"Javascript has the concept of generators. They are critical to this problem.",
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"First yield 0 and 1.",
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