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批量更新数据

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2025-01-09 20:29:41 +08:00
parent 04ecea043d
commit 48cdd06c2b
5053 changed files with 156164 additions and 135322 deletions

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@@ -12,12 +12,12 @@
"translatedContent": "<p>Table:&nbsp;<code>Activity</code></p>\n\n<pre>\n+--------------+---------+\n| Column Name | Type |\n+--------------+---------+\n| player_id | int |\n| device_id | int |\n| event_date | date |\n| games_played | int |\n+--------------+---------+\nplayer_idevent_date是此表的主键具有唯一值的列的组合。\n这张表显示了某些游戏的玩家的活动情况。\n每一行是一个玩家的记录他在某一天使用某个设备注销之前登录并玩了很多游戏可能是 0。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>编写解决方案,报告在首次登录的第二天再次登录的玩家的 <strong>比率</strong><strong>四舍五入到小数点后两位</strong>。换句话说,你需要计算从首次登录日期开始至少连续两天登录的玩家的数量,然后除以玩家总数。</p>\n\n<p>结果格式如下所示:</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>\nActivity table:\n+-----------+-----------+------------+--------------+\n| player_id | device_id | event_date | games_played |\n+-----------+-----------+------------+--------------+\n| 1 | 2 | 2016-03-01 | 5 |\n| 1 | 2 | 2016-03-02 | 6 |\n| 2 | 3 | 2017-06-25 | 1 |\n| 3 | 1 | 2016-03-02 | 0 |\n| 3 | 4 | 2018-07-03 | 5 |\n+-----------+-----------+------------+--------------+\n<strong>输出:</strong>\n+-----------+\n| fraction |\n+-----------+\n| 0.33 |\n+-----------+\n<strong>解释:</strong>\n只有 ID 为 1 的玩家在第一天登录后才重新登录,所以答案是 1/3 = 0.33\n</pre>\n",
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@@ -77,7 +77,7 @@
"insert into Activity (player_id, device_id, event_date, games_played) values ('3', '4', '2018-07-03', '5')"
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