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2025-01-09 20:29:41 +08:00
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commit 48cdd06c2b
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leetcode-cn/originData/find-total-time-spent-by-each-employee.json
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@@ -12,12 +12,12 @@
"translatedContent": "<p>表: <code>Employees</code></p>\n\n<pre>\n+-------------+------+\n| Column Name | Type |\n+-------------+------+\n| emp_id | int |\n| event_day | date |\n| in_time | int |\n| out_time | int |\n+-------------+------+\n在 SQL 中，(emp_id, event_day, in_time) 是这个表的主键。\n该表显示了员工在办公室的出入情况。\nevent_day 是此事件发生的日期，in_time 是员工进入办公室的时间，而 out_time 是他们离开办公室的时间。\nin_time 和 out_time 的取值在1到1440之间。\n题目保证同一天没有两个事件在时间上是相交的，并且保证 in_time 小于 out_time。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>计算每位员工每天在办公室花费的总时间（以分钟为单位）。 请注意，在一天之内，同一员工是可以多次进入和离开办公室的。 在办公室里一次进出所花费的时间为out_time 减去 in_time。</p>\n\n<p>返回结果表单的顺序无要求。<br />\n查询结果的格式如下：</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>\nEmployees table:\n+--------+------------+---------+----------+\n| emp_id | event_day | in_time | out_time |\n+--------+------------+---------+----------+\n| 1 | 2020-11-28 | 4 | 32 |\n| 1 | 2020-11-28 | 55 | 200 |\n| 1 | 2020-12-03 | 1 | 42 |\n| 2 | 2020-11-28 | 3 | 33 |\n| 2 | 2020-12-09 | 47 | 74 |\n+--------+------------+---------+----------+\n<strong>输出：</strong>\n+------------+--------+------------+\n| day | emp_id | total_time |\n+------------+--------+------------+\n| 2020-11-28 | 1 | 173 |\n| 2020-11-28 | 2 | 30 |\n| 2020-12-03 | 1 | 41 |\n| 2020-12-09 | 2 | 27 |\n+------------+--------+------------+\n<strong>解释：</strong>\n雇员 1 有三次进出: 有两次发生在 2020-11-28 花费的时间为 (32 - 4) + (200 - 55) = 173, 有一次发生在 2020-12-03 花费的时间为 (42 - 1) = 41。\n雇员 2 有两次进出: 有一次发生在 2020-11-28 花费的时间为 (33 - 3) = 30, 有一次发生在 2020-12-09 花费的时间为 (74 - 47) = 27。\n</pre>\n",
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@@ -59,7 +59,7 @@
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@@ -77,7 +77,7 @@
"insert into Employees (emp_id, event_day, in_time, out_time) values ('2', '2020-12-9', '47', '74')"
],
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