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https://gitee.com/coder-xiaomo/leetcode-problemset
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批量更新数据
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@@ -7,17 +7,17 @@
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"title": "Exchange Seats",
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"titleSlug": "exchange-seats",
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"content": "<p>Table: <code>Seat</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| id | int |\n| student | varchar |\n+-------------+---------+\nid is the primary key (unique value) column for this table.\nEach row of this table indicates the name and the ID of a student.\nid is a continuous increment.\n</pre>\n\n<p> </p>\n\n<p>Write a solution to swap the seat id of every two consecutive students. If the number of students is odd, the id of the last student is not swapped.</p>\n\n<p>Return the result table ordered by <code>id</code> <strong>in ascending order</strong>.</p>\n\n<p>The result format is in the following example.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nSeat table:\n+----+---------+\n| id | student |\n+----+---------+\n| 1 | Abbot |\n| 2 | Doris |\n| 3 | Emerson |\n| 4 | Green |\n| 5 | Jeames |\n+----+---------+\n<strong>Output:</strong> \n+----+---------+\n| id | student |\n+----+---------+\n| 1 | Doris |\n| 2 | Abbot |\n| 3 | Green |\n| 4 | Emerson |\n| 5 | Jeames |\n+----+---------+\n<strong>Explanation:</strong> \nNote that if the number of students is odd, there is no need to change the last one's seat.\n</pre>\n",
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"content": "<p>Table: <code>Seat</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| id | int |\n| student | varchar |\n+-------------+---------+\nid is the primary key (unique value) column for this table.\nEach row of this table indicates the name and the ID of a student.\nThe ID sequence always starts from 1 and increments continuously.\n</pre>\n\n<p> </p>\n\n<p>Write a solution to swap the seat id of every two consecutive students. If the number of students is odd, the id of the last student is not swapped.</p>\n\n<p>Return the result table ordered by <code>id</code> <strong>in ascending order</strong>.</p>\n\n<p>The result format is in the following example.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nSeat table:\n+----+---------+\n| id | student |\n+----+---------+\n| 1 | Abbot |\n| 2 | Doris |\n| 3 | Emerson |\n| 4 | Green |\n| 5 | Jeames |\n+----+---------+\n<strong>Output:</strong> \n+----+---------+\n| id | student |\n+----+---------+\n| 1 | Doris |\n| 2 | Abbot |\n| 3 | Green |\n| 4 | Emerson |\n| 5 | Jeames |\n+----+---------+\n<strong>Explanation:</strong> \nNote that if the number of students is odd, there is no need to change the last one's seat.\n</pre>\n",
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"translatedTitle": "换座位",
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"translatedContent": "<p>表: <code>Seat</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| id | int |\n| student | varchar |\n+-------------+---------+\n<code>id</code> 是该表的主键(唯一值)列。\n该表的每一行都表示学生的姓名和 ID。\nid 是一个连续的增量。\n</pre>\n\n<p> </p>\n\n<p>编写解决方案来交换每两个连续的学生的座位号。如果学生的数量是奇数,则最后一个学生的id不交换。</p>\n\n<p>按 <code>id</code> <strong>升序</strong> 返回结果表。</p>\n\n<p>查询结果格式如下所示。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> \nSeat 表:\n+----+---------+\n| id | student |\n+----+---------+\n| 1 | Abbot |\n| 2 | Doris |\n| 3 | Emerson |\n| 4 | Green |\n| 5 | Jeames |\n+----+---------+\n<strong>输出:</strong> \n+----+---------+\n| id | student |\n+----+---------+\n| 1 | Doris |\n| 2 | Abbot |\n| 3 | Green |\n| 4 | Emerson |\n| 5 | Jeames |\n+----+---------+\n<strong>解释:\n</strong>请注意,如果学生人数为奇数,则不需要更换最后一名学生的座位。</pre>\n",
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"translatedContent": "<p>表: <code>Seat</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| id | int |\n| student | varchar |\n+-------------+---------+\n<code>id</code> 是该表的主键(唯一值)列。\n该表的每一行都表示学生的姓名和 ID。\nID 序列始终从 1 开始并连续增加。\n</pre>\n\n<p> </p>\n\n<p>编写解决方案来交换每两个连续的学生的座位号。如果学生的数量是奇数,则最后一个学生的id不交换。</p>\n\n<p>按 <code>id</code> <strong>升序</strong> 返回结果表。</p>\n\n<p>查询结果格式如下所示。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> \nSeat 表:\n+----+---------+\n| id | student |\n+----+---------+\n| 1 | Abbot |\n| 2 | Doris |\n| 3 | Emerson |\n| 4 | Green |\n| 5 | Jeames |\n+----+---------+\n<strong>输出:</strong> \n+----+---------+\n| id | student |\n+----+---------+\n| 1 | Doris |\n| 2 | Abbot |\n| 3 | Green |\n| 4 | Emerson |\n| 5 | Jeames |\n+----+---------+\n<strong>解释:\n</strong>请注意,如果学生人数为奇数,则不需要更换最后一名学生的座位。</pre>\n",
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@@ -77,7 +77,7 @@
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"insert into Seat (id, student) values ('5', 'Jeames')"
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