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mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-09-07 00:11:41 +08:00
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批量更新数据

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2025-01-09 20:29:41 +08:00
parent 04ecea043d
commit 48cdd06c2b
5053 changed files with 156164 additions and 135322 deletions

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@@ -12,12 +12,12 @@
"translatedContent": "<p>表:<code>Employee</code>&nbsp;</p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| empId | int |\n| name | varchar |\n| supervisor | int |\n| salary | int |\n+-------------+---------+\nempId 是该表中具有唯一值的列。\n该表的每一行都表示员工的姓名和 id以及他们的工资和经理的 id。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>表:<code>Bonus</code></p>\n\n<pre>\n+-------------+------+\n| Column Name | Type |\n+-------------+------+\n| empId | int |\n| bonus | int |\n+-------------+------+\nempId 是该表具有唯一值的列。\nempId 是 Employee 表中 empId 的外键(reference 列)。\n该表的每一行都包含一个员工的 id 和他们各自的奖金。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>编写解决方案,报告每个奖金 <strong>少于</strong> <code>1000</code> 的员工的姓名和奖金数额。</p>\n\n<p>以 <strong>任意顺序</strong> 返回结果表。</p>\n\n<p>结果格式如下所示。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<b>输入:</b>\nEmployee table:\n+-------+--------+------------+--------+\n| empId | name | supervisor | salary |\n+-------+--------+------------+--------+\n| 3 | Brad | null | 4000 |\n| 1 | John | 3 | 1000 |\n| 2 | Dan | 3 | 2000 |\n| 4 | Thomas | 3 | 4000 |\n+-------+--------+------------+--------+\nBonus table:\n+-------+-------+\n| empId | bonus |\n+-------+-------+\n| 2 | 500 |\n| 4 | 2000 |\n+-------+-------+\n<b>输出:</b>\n+------+-------+\n| name | bonus |\n+------+-------+\n| Brad | null |\n| John | null |\n| Dan | 500 |\n+------+-------+</pre>\n",
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"difficulty": "Easy",
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"similarQuestions": "[{\"title\": \"Combine Two Tables\", \"titleSlug\": \"combine-two-tables\", \"difficulty\": \"Easy\", \"translatedTitle\": \"\\u7ec4\\u5408\\u4e24\\u4e2a\\u8868\", \"isPaidOnly\": false}]",
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"name": "Database",
@@ -59,7 +59,7 @@
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"hints": [
"If the EmpId in table Employee has no match in table Bonus, we consider that the corresponding bonus is null and null is smaller than 1000.",
"Inner join is the default join, we can solve the mismatching problem by using outer join."
@@ -74,7 +74,7 @@
"Create table If Not Exists Employee (empId int, name varchar(255), supervisor int, salary int)",
"Create table If Not Exists Bonus (empId int, bonus int)",
"Truncate table Employee",
"insert into Employee (empId, name, supervisor, salary) values ('3', 'Brad', 'None', '4000')",
"insert into Employee (empId, name, supervisor, salary) values ('3', 'Brad', NULL, '4000')",
"insert into Employee (empId, name, supervisor, salary) values ('1', 'John', '3', '1000')",
"insert into Employee (empId, name, supervisor, salary) values ('2', 'Dan', '3', '2000')",
"insert into Employee (empId, name, supervisor, salary) values ('4', 'Thomas', '3', '4000')",
@@ -83,7 +83,7 @@
"insert into Bonus (empId, bonus) values ('4', '2000')"
],
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