mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-09-05 23:41:41 +08:00
update
This commit is contained in:
zhangbk1
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||||
{
|
||||
"data": {
|
||||
"question": {
|
||||
"questionId": "3409",
|
||||
"questionFrontendId": "3103",
|
||||
"categoryTitle": "Database",
|
||||
"boundTopicId": 2719939,
|
||||
"title": "Find Trending Hashtags II ",
|
||||
"titleSlug": "find-trending-hashtags-ii",
|
||||
"content": null,
|
||||
"translatedTitle": "查找热门话题标签 II",
|
||||
"translatedContent": null,
|
||||
"isPaidOnly": true,
|
||||
"difficulty": "Hard",
|
||||
"likes": 0,
|
||||
"dislikes": 0,
|
||||
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"similarQuestions": "[]",
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||||
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|
||||
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|
||||
"topicTags": [
|
||||
{
|
||||
"name": "Database",
|
||||
"slug": "database",
|
||||
"translatedName": "数据库",
|
||||
"__typename": "TopicTagNode"
|
||||
}
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],
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||||
"companyTagStats": null,
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||||
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"stats": "{\"totalAccepted\": \"10\", \"totalSubmission\": \"60\", \"totalAcceptedRaw\": 10, \"totalSubmissionRaw\": 60, \"acRate\": \"16.7%\"}",
|
||||
"hints": [],
|
||||
"solution": null,
|
||||
"status": null,
|
||||
"sampleTestCase": "{\"headers\":{\"Tweets\":[\"user_id\",\"tweet_id\",\"tweet\",\"tweet_date\"]},\"rows\":{\"Tweets\":[[135,13,\"Enjoying a great start to the day. #HappyDay #MorningVibes\",\"2024-02-01\"],[136,14,\"Another #HappyDay with good vibes! #FeelGood\",\"2024-02-03\"],[137,15,\"Productivity peaks! #WorkLife #ProductiveDay\",\"2024-02-04\"],[138,16,\"Exploring new tech frontiers. #TechLife #Innovation\",\"2024-02-04\"],[139,17,\"Gratitude for today's moments. #HappyDay #Thankful\",\"2024-02-05\"],[140,18,\"Innovation drives us. #TechLife #FutureTech\",\"2024-02-07\"],[141,19,\"Connecting with nature's serenity. #Nature #Peaceful\",\"2024-02-09\"]]}}",
|
||||
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||||
"judgerAvailable": true,
|
||||
"judgeType": "large",
|
||||
"mysqlSchemas": [
|
||||
"Create table If Not Exists Tweets (user_id int, tweet_id int, tweet_date date, tweet varchar(100))",
|
||||
"Truncate table Tweets",
|
||||
"insert into Tweets (user_id, tweet_id, tweet, tweet_date) values ('135', '13', 'Enjoying a great start to the day. #HappyDay #MorningVibes', '2024-02-01')",
|
||||
"insert into Tweets (user_id, tweet_id, tweet, tweet_date) values ('136', '14', 'Another #HappyDay with good vibes! #FeelGood', '2024-02-03')",
|
||||
"insert into Tweets (user_id, tweet_id, tweet, tweet_date) values ('137', '15', 'Productivity peaks! #WorkLife #ProductiveDay', '2024-02-04')",
|
||||
"insert into Tweets (user_id, tweet_id, tweet, tweet_date) values ('138', '16', 'Exploring new tech frontiers. #TechLife #Innovation', '2024-02-04')",
|
||||
"insert into Tweets (user_id, tweet_id, tweet, tweet_date) values ('139', '17', 'Gratitude for today's moments. #HappyDay #Thankful', '2024-02-05')",
|
||||
"insert into Tweets (user_id, tweet_id, tweet, tweet_date) values ('140', '18', 'Innovation drives us. #TechLife #FutureTech', '2024-02-07')",
|
||||
"insert into Tweets (user_id, tweet_id, tweet, tweet_date) values ('141', '19', 'Connecting with nature's serenity. #Nature #Peaceful', '2024-02-09')"
|
||||
],
|
||||
"enableRunCode": true,
|
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"envInfo": "{\"mysql\":[\"MySQL\",\"<p>\\u7248\\u672c\\uff1a<code>MySQL 8.0<\\/code><\\/p>\"],\"mssql\":[\"MS SQL Server\",\"<p>mssql server 2019.<\\/p>\"],\"oraclesql\":[\"Oracle\",\"<p>Oracle Sql 11.2.<\\/p>\"],\"pythondata\":[\"Pandas\",\"<p>Python 3.10 with Pandas 2.0.2 and NumPy 1.25.0<\\/p>\"],\"postgresql\":[\"PostgreSQL\",\"<p>PostgreSQL 16<\\/p>\"]}",
|
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"book": null,
|
||||
"isSubscribed": false,
|
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"isDailyQuestion": false,
|
||||
"dailyRecordStatus": null,
|
||||
"editorType": "CKEDITOR",
|
||||
"ugcQuestionId": null,
|
||||
"style": "LEETCODE",
|
||||
"exampleTestcases": "{\"headers\":{\"Tweets\":[\"user_id\",\"tweet_id\",\"tweet\",\"tweet_date\"]},\"rows\":{\"Tweets\":[[135,13,\"Enjoying a great start to the day. #HappyDay #MorningVibes\",\"2024-02-01\"],[136,14,\"Another #HappyDay with good vibes! #FeelGood\",\"2024-02-03\"],[137,15,\"Productivity peaks! #WorkLife #ProductiveDay\",\"2024-02-04\"],[138,16,\"Exploring new tech frontiers. #TechLife #Innovation\",\"2024-02-04\"],[139,17,\"Gratitude for today's moments. #HappyDay #Thankful\",\"2024-02-05\"],[140,18,\"Innovation drives us. #TechLife #FutureTech\",\"2024-02-07\"],[141,19,\"Connecting with nature's serenity. #Nature #Peaceful\",\"2024-02-09\"]]}}",
|
||||
"__typename": "QuestionNode"
|
||||
}
|
||||
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|
||||
}
|
||||
178
leetcode-cn/originData/count-alternating-subarrays.json
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leetcode-cn/originData/count-alternating-subarrays.json
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leetcode-cn/originData/find-the-sum-of-subsequence-powers.json
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leetcode-cn/originData/find-the-sum-of-subsequence-powers.json
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leetcode-cn/originData/harshad-number.json
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leetcode-cn/originData/harshad-number.json
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leetcode-cn/originData/minimize-manhattan-distances.json
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leetcode-cn/originData/minimize-manhattan-distances.json
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leetcode-cn/originData/minimum-cost-walk-in-weighted-graph.json
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leetcode-cn/originData/minimum-cost-walk-in-weighted-graph.json
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leetcode-cn/originData/minimum-levels-to-gain-more-points.json
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leetcode-cn/originData/minimum-levels-to-gain-more-points.json
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leetcode-cn/originData/water-bottles-ii.json
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leetcode-cn/originData/water-bottles-ii.json
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|
||||
<p>给你一个<span data-keyword="binary-array">二进制数组 </span><code>nums</code> 。</p>
|
||||
|
||||
<p>如果一个<span data-keyword="subarray-nonempty">子数组</span>中 <strong>不存在 </strong>两个 <strong>相邻 </strong>元素的值 <strong>相同</strong> 的情况，我们称这样的子数组为 <strong>交替子数组 </strong>。</p>
|
||||
|
||||
<p>返回数组 <code>nums</code> 中交替子数组的数量。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>输入：</strong> <span class="example-io">nums = [0,1,1,1]</span></p>
|
||||
|
||||
<p><strong>输出：</strong> <span class="example-io">5</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
<!-- 解释示例1的交替子数组 -->
|
||||
|
||||
<p>以下子数组是交替子数组：<code>[0]</code> 、<code>[1]</code> 、<code>[1]</code> 、<code>[1]</code> 以及 <code>[0,1]</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>输入：</strong> <span class="example-io">nums = [1,0,1,0]</span></p>
|
||||
|
||||
<p><strong>输出：</strong> <span class="example-io">10</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
<!-- 解释示例2的交替子数组 -->
|
||||
|
||||
<p>数组的每个子数组都是交替子数组。可以统计在内的子数组共有 10 个。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>nums[i]</code> 不是 <code>0</code> 就是 <code>1</code> 。</li>
|
||||
</ul>
|
||||
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|
||||
<p>给你一个整数数组 <code>nums</code> 和一个 <strong>非负</strong> 整数 <code>k</code> 。</p>
|
||||
|
||||
<p>一次操作中，你可以选择任一下标 <code>i</code> ，然后将 <code>nums[i]</code> 加 <code>1</code> 或者减 <code>1</code> 。</p>
|
||||
|
||||
<p>请你返回将 <code>nums</code> <strong>中位数</strong> 变为 <code>k</code> 所需要的 <strong>最少</strong> 操作次数。</p>
|
||||
|
||||
<p>一个数组的 <strong>中位数</strong> 指的是数组按 <strong>非递减</strong> 顺序排序后最中间的元素。如果数组长度为偶数，我们选择中间两个数的较大值为中位数。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [2,5,6,8,5], k = 4</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>2</span></p>
|
||||
|
||||
<p><b>解释：</b>我们将 <code>nums[1]</code> 和 <code>nums[4]</code> 减 <code>1</code> 得到 <code>[2, 4, 6, 8, 4]</code> 。现在数组的中位数等于 <code>k</code> 。所以答案为 2 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [2,5,6,8,5], k = 7</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>3</span></p>
|
||||
|
||||
<p><b>解释：</b>我们将 <code>nums[1]</code> 增加 1 两次，并且将 <code>nums[2]</code> 增加 1 一次，得到 <code>[2, 7, 7, 8, 5]</code> 。结果数组的中位数等于 <code>k</code> 。所以答案为 3 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 3：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [1,2,3,4,5,6], k = 4</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>0</span></p>
|
||||
|
||||
<p><b>解释：</b>数组中位数已经等于 <code>k</code> 了，所以不需要进行任何操作。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 2 * 10<sup>5</sup></code></li>
|
||||
<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>
|
||||
<li><code>1 <= k <= 10<sup>9</sup></code></li>
|
||||
</ul>
|
||||
35
leetcode-cn/problem (Chinese)/哈沙德数 [harshad-number].html
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leetcode-cn/problem (Chinese)/哈沙德数 [harshad-number].html
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|
||||
<p>如果一个整数能够被其各个数位上的数字之和整除，则称之为<strong> 哈沙德数</strong>（Harshad number）。给你一个整数 <code>x</code> 。如果 <code>x</code> 是 <strong>哈沙德数 </strong>，则返回<em> </em><code>x</code> 各个数位上的数字之和，否则，返回<em> </em><code>-1</code> 。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>输入：</strong> <span class="example-io">x = 18</span></p>
|
||||
|
||||
<p><strong>输出：</strong> <span class="example-io">9</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><code>x</code> 各个数位上的数字之和为 <code>9</code> 。<code>18</code> 能被 <code>9</code> 整除。因此 <code>18</code> 是哈沙德数，答案是 <code>9</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>输入：</strong> <span class="example-io">x = 23</span></p>
|
||||
|
||||
<p><strong>输出：</strong> <span class="example-io">-1</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><code>x</code> 各个数位上的数字之和为 <code>5</code> 。<code>23</code> 不能被 <code>5</code> 整除。因此 <code>23</code> 不是哈沙德数，答案是 <code>-1</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= x <= 100</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,59 @@
|
||||
<p>给你一个 <code>n</code> 个节点的带权无向图，节点编号为 <code>0</code> 到 <code>n - 1</code> 。</p>
|
||||
|
||||
<p>给你一个整数 <code>n</code> 和一个数组 <code>edges</code> ，其中 <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>, w<sub>i</sub>]</code> 表示节点 <code>u<sub>i</sub></code> 和 <code>v<sub>i</sub></code> 之间有一条权值为 <code>w<sub>i</sub></code> 的无向边。</p>
|
||||
|
||||
<p>在图中，一趟旅途包含一系列节点和边。旅途开始和结束点都是图中的节点，且图中存在连接旅途中相邻节点的边。注意，一趟旅途可能访问同一条边或者同一个节点多次。</p>
|
||||
|
||||
<p>如果旅途开始于节点 <code>u</code> ，结束于节点 <code>v</code> ，我们定义这一趟旅途的 <strong>代价</strong> 是经过的边权按位与 <code>AND</code> 的结果。换句话说，如果经过的边对应的边权为 <code>w<sub>0</sub>, w<sub>1</sub>, w<sub>2</sub>, ..., w<sub>k</sub></code> ，那么代价为<code>w<sub>0</sub> & w<sub>1</sub> & w<sub>2</sub> & ... & w<sub>k</sub></code> ，其中 <code>&</code> 表示按位与 <code>AND</code> 操作。</p>
|
||||
|
||||
<p>给你一个二维数组 <code>query</code> ，其中 <code>query[i] = [s<sub>i</sub>, t<sub>i</sub>]</code> 。对于每一个查询，你需要找出从节点开始 <code>s<sub>i</sub></code> ，在节点 <code>t<sub>i</sub></code> 处结束的旅途的最小代价。如果不存在这样的旅途，答案为 <code>-1</code> 。</p>
|
||||
|
||||
<p>返回数组<em> </em><code>answer</code> ，其中<em> </em><code>answer[i]</code><em> </em>表示对于查询 <code>i</code> 的 <strong>最小</strong> 旅途代价。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>n = 5, edges = [[0,1,7],[1,3,7],[1,2,1]], query = [[0,3],[3,4]]</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>[1,-1]</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><img alt="" src="https://assets.leetcode.com/uploads/2024/01/31/q4_example1-1.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 351px; height: 141px;" /></p>
|
||||
|
||||
<p>第一个查询想要得到代价为 1 的旅途，我们依次访问：<code>0->1</code>（边权为 7 ）<code>1->2</code> （边权为 1 ）<code>2->1</code>（边权为 1 ）<code>1->3</code> （边权为 7 ）。</p>
|
||||
|
||||
<p>第二个查询中，无法从节点 3 到节点 4 ，所以答案为 -1 。</p>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
</div>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>n = 3, edges = [[0,2,7],[0,1,15],[1,2,6],[1,2,1]], query = [[1,2]]</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>[0]</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><img alt="" src="https://assets.leetcode.com/uploads/2024/01/31/q4_example2e.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 211px; height: 181px;" /></p>
|
||||
|
||||
<p>第一个查询想要得到代价为 0 的旅途，我们依次访问：<code>1->2</code>（边权为 1 ），<code>2->1</code>（边权 为 6 ），<code>1->2</code>（边权为 1 ）。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= n <= 10<sup>5</sup></code></li>
|
||||
<li><code>0 <= edges.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>edges[i].length == 3</code></li>
|
||||
<li><code>0 <= u<sub>i</sub>, v<sub>i</sub> <= n - 1</code></li>
|
||||
<li><code>u<sub>i</sub> != v<sub>i</sub></code></li>
|
||||
<li><code>0 <= w<sub>i</sub> <= 10<sup>5</sup></code></li>
|
||||
<li><code>1 <= query.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>query[i].length == 2</code></li>
|
||||
<li><code>0 <= s<sub>i</sub>, t<sub>i</sub> <= n - 1</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,75 @@
|
||||
<p>给你一个长度为 <code>n</code> 的二进制数组 <code>possible</code> 。</p>
|
||||
|
||||
<p>莉叩酱和冬坂五百里正在玩一个有 <code>n</code> 个关卡的游戏，游戏中有一些关卡是 <strong>困难</strong> 模式，其他的关卡是 <strong>简单</strong> 模式。如果 <code>possible[i] == 0</code> ，那么第 <code>i</code> 个关卡是 <strong>困难</strong> 模式。一个玩家通过一个简单模式的关卡可以获得 <code>1</code> 分，通过困难模式的关卡将失去 <code>1</code> 分。</p>
|
||||
|
||||
<p>游戏的一开始，莉叩酱将从第 <code>0</code> 级开始 <strong>按顺序</strong> 完成一些关卡，然后冬坂五百里会完成剩下的所有关卡。</p>
|
||||
|
||||
<p>假设两名玩家都采取最优策略，目的是 <strong>最大化</strong> 自己的得分，莉叩酱想知道自己 <strong>最少</strong> 需要完成多少个关卡，才能获得比冬坂五百里更多的分数。</p>
|
||||
|
||||
<p>请你返回莉叩酱获得比冬坂五百里更多的分数所需要完成的 <strong>最少</strong> 关卡数目，如果 <strong>无法</strong> 达成，那么返回 <code>-1</code> 。</p>
|
||||
|
||||
<p><strong>注意</strong>，每个玩家都至少需要完成 <code>1</code> 个关卡。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>possible = [1,0,1,0]</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>1</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p>我们来看一下莉叩酱可以完成的关卡数目：</p>
|
||||
|
||||
<ul>
|
||||
<li>如果莉叩酱只完成关卡 0 ，冬坂五百里完成剩下的所有关卡，那么莉叩酱获得 1 分，冬坂五百里获得 -1 + 1 - 1 = -1 分。</li>
|
||||
<li>如果莉叩酱完成到关卡 1 ，冬坂五百里完成剩下的所有关卡，那么莉叩酱获得 1 - 1 = 0 分，冬坂五百里获得 1 - 1 = 0 分。</li>
|
||||
<li>如果莉叩酱完成到关卡 2 ，冬坂五百里完成剩下的所有关卡，那么莉叩酱获得 1 - 1 + 1 = 1 分，冬坂五百里获得 -1 分。</li>
|
||||
</ul>
|
||||
|
||||
<p>莉叩酱需要完成至少一个关卡获得更多的分数。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>possible = [1,1,1,1,1]</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>3</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p>我们来看一下莉叩酱可以完成的关卡数目：</p>
|
||||
|
||||
<ul>
|
||||
<li>如果莉叩酱只完成关卡 0 ，冬坂五百里完成剩下的所有关卡，那么莉叩酱获得 1 分，冬坂五百里获得 4 分。</li>
|
||||
<li>如果莉叩酱完成到关卡 1 ，冬坂五百里完成剩下的所有关卡，那么莉叩酱获得 2 分，冬坂五百里获得 3 分。</li>
|
||||
<li>如果莉叩酱完成到关卡 2 ，冬坂五百里完成剩下的所有关卡，那么莉叩酱获得 3 分，冬坂五百里获得 2 分。</li>
|
||||
<li>如果莉叩酱完成到关卡 3 ，冬坂五百里完成剩下的所有关卡，那么莉叩酱获得 4 分，冬坂五百里获得 1 分。</li>
|
||||
</ul>
|
||||
|
||||
<p>莉叩酱需要完成至少三个关卡获得更多的分数。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 3：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>possible = [0,0]</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>-1</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p>两名玩家只能各完成 1 个关卡，莉叩酱完成关卡 0 得到 -1 分，冬坂五百里完成关卡 1 得到 -1 分。两名玩家得分相同，所以莉叩酱无法得到更多分数。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>2 <= n == possible.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>possible[i]</code> 要么是 <code>0</code> 要么是 <code>1</code> 。</li>
|
||||
</ul>
|
||||
@@ -0,0 +1,53 @@
|
||||
<p>给你一个 <strong>非负</strong> 整数数组 <code>nums</code> 和一个整数 <code>k</code> 。</p>
|
||||
|
||||
<p>如果一个数组中所有元素的按位或运算 <code>OR</code> 的值 <strong>至少</strong> 为 <code>k</code> ，那么我们称这个数组是 <strong>特别的</strong> 。</p>
|
||||
|
||||
<p>请你返回 <code>nums</code> 中 <strong>最短特别非空</strong> <span data-keyword="subarray-nonempty">子数组</span>的长度，如果特别子数组不存在，那么返回 <code>-1</code> 。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [1,2,3], k = 2</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>1</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p>子数组 <code>[3]</code> 的按位 <code>OR</code> 值为 <code>3</code> ，所以我们返回 <code>1</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [2,1,8], k = 10</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>3</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p>子数组 <code>[2,1,8]</code> 的按位 <code>OR</code> 值为 <code>11</code> ，所以我们返回 <code>3</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 3：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [1,2], k = 0</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>1</span></p>
|
||||
|
||||
<p><b>解释：</b></p>
|
||||
|
||||
<p>子数组 <code>[1]</code> 的按位 <code>OR</code> 值为 <code>1</code> ，所以我们返回 <code>1</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 50</code></li>
|
||||
<li><code>0 <= nums[i] <= 50</code></li>
|
||||
<li><code>0 <= k < 64</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,53 @@
|
||||
<p>给你一个 <strong>非负</strong> 整数数组 <code>nums</code> 和一个整数 <code>k</code> 。</p>
|
||||
|
||||
<p>如果一个数组中所有元素的按位或运算 <code>OR</code> 的值 <strong>至少</strong> 为 <code>k</code> ，那么我们称这个数组是 <strong>特别的</strong> 。</p>
|
||||
|
||||
<p>请你返回 <code>nums</code> 中 <strong>最短特别非空</strong> <span data-keyword="subarray-nonempty">子数组</span>的长度，如果特别子数组不存在，那么返回 <code>-1</code> 。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [1,2,3], k = 2</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>1</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p>子数组 <code>[3]</code> 的按位 <code>OR</code> 值为 <code>3</code> ，所以我们返回 <code>1</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [2,1,8], k = 10</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>3</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p>子数组 <code>[2,1,8]</code> 的按位 <code>OR</code> 值为 <code>11</code> ，所以我们返回 <code>3</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 3：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [1,2], k = 0</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>1</span></p>
|
||||
|
||||
<p><b>解释：</b></p>
|
||||
|
||||
<p>子数组 <code>[1]</code> 的按位 <code>OR</code> 值为 <code>1</code> ，所以我们返回 <code>1</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 2 * 10<sup>5</sup></code></li>
|
||||
<li><code>0 <= nums[i] <= 10<sup><font size="1">9</font></sup></code></li>
|
||||
<li><code>0 <= k <= 10<sup>9</sup></code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,38 @@
|
||||
<p>给你两个整数 <code>numBottles</code> 和 <code>numExchange</code> 。</p>
|
||||
|
||||
<p><code>numBottles</code> 代表你最初拥有的满水瓶数量。在一次操作中，你可以执行以下操作之一：</p>
|
||||
|
||||
<ul>
|
||||
<li>喝掉任意数量的满水瓶，使它们变成空水瓶。</li>
|
||||
<li>用 <code>numExchange</code> 个空水瓶交换一个满水瓶。然后，将 <code>numExchange</code> 的值增加 1 。</li>
|
||||
</ul>
|
||||
|
||||
<p>注意，你不能使用相同的 <code>numExchange</code> 值交换多批空水瓶。例如，如果 <code>numBottles == 3</code> 并且 <code>numExchange == 1</code> ，则不能用 <code>3</code> 个空水瓶交换成 <code>3</code> 个满水瓶。</p>
|
||||
|
||||
<p>返回你 <strong>最多</strong> 可以喝到多少瓶水。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
<img alt="" src="https://assets.leetcode.com/uploads/2024/01/28/exampleone1.png" style="width: 948px; height: 482px; padding: 10px; background: #fff; border-radius: .5rem;" />
|
||||
<pre>
|
||||
<strong>输入：</strong>numBottles = 13, numExchange = 6
|
||||
<strong>输出：</strong>15
|
||||
<strong>解释：</strong>上表显示了满水瓶的数量、空水瓶的数量、numExchange 的值，以及累计喝掉的水瓶数量。
|
||||
</pre>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
<img alt="" src="https://assets.leetcode.com/uploads/2024/01/28/example231.png" style="width: 990px; height: 642px; padding: 10px; background: #fff; border-radius: .5rem;" />
|
||||
<pre>
|
||||
<strong>输入：</strong>numBottles = 10, numExchange = 3
|
||||
<strong>输出：</strong>13
|
||||
<strong>解释：</strong>上表显示了满水瓶的数量、空水瓶的数量、numExchange 的值，以及累计喝掉的水瓶数量。</pre>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= numBottles <= 100 </code></li>
|
||||
<li><code>1 <= numExchange <= 100</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,38 @@
|
||||
<p>给你一个下标从 <strong>0</strong> 开始的数组 <code>points</code> ，它表示二维平面上一些点的整数坐标，其中 <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> 。</p>
|
||||
|
||||
<p>两点之间的距离定义为它们的<span data-keyword="manhattan-distance">曼哈顿距离</span>。</p>
|
||||
|
||||
<p>请你恰好移除一个点，返回移除后任意两点之间的 <strong>最大 </strong>距离可能的 <strong>最小 </strong>值。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<pre>
|
||||
<strong>输入：</strong>points = [[3,10],[5,15],[10,2],[4,4]]
|
||||
<strong>输出：</strong>12
|
||||
<strong>解释：</strong>移除每个点后的最大距离如下所示：
|
||||
- 移除第 0 个点后，最大距离在点 (5, 15) 和 (10, 2) 之间，为 |5 - 10| + |15 - 2| = 18 。
|
||||
- 移除第 1 个点后，最大距离在点 (3, 10) 和 (10, 2) 之间，为 |3 - 10| + |10 - 2| = 15 。
|
||||
- 移除第 2 个点后，最大距离在点 (5, 15) 和 (4, 4) 之间，为 |5 - 4| + |15 - 4| = 12 。
|
||||
- 移除第 3 个点后，最大距离在点 (5, 15) 和 (10, 2) 之间的，为 |5 - 10| + |15 - 2| = 18 。
|
||||
在恰好移除一个点后，任意两点之间的最大距离可能的最小值是 12 。
|
||||
</pre>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<pre>
|
||||
<strong>输入：</strong>points = [[1,1],[1,1],[1,1]]
|
||||
<strong>输出：</strong>0
|
||||
<strong>解释：</strong>移除任一点后，任意两点之间的最大距离都是 0 。
|
||||
</pre>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>3 <= points.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>points[i].length == 2</code></li>
|
||||
<li><code>1 <= points[i][0], points[i][1] <= 10<sup>8</sup></code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,62 @@
|
||||
<p>给你一个整数数组 <code>nums</code> 。</p>
|
||||
|
||||
<p>返回数组 <code>nums</code> 中<strong> 严格递增 </strong>或 <strong>严格递减 </strong>的最长非空子数组的长度。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>输入：</strong><span class="example-io">nums = [1,4,3,3,2]</span></p>
|
||||
|
||||
<p><strong>输出：</strong><span class="example-io">2</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><code>nums</code> 中严格递增的子数组有<code>[1]</code>、<code>[2]</code>、<code>[3]</code>、<code>[3]</code>、<code>[4]</code> 以及 <code>[1,4]</code> 。</p>
|
||||
|
||||
<p><code>nums</code> 中严格递减的子数组有<code>[1]</code>、<code>[2]</code>、<code>[3]</code>、<code>[3]</code>、<code>[4]</code>、<code>[3,2]</code> 以及 <code>[4,3]</code> 。</p>
|
||||
|
||||
<p>因此，返回 <code>2</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>输入：</strong><span class="example-io">nums = [3,3,3,3]</span></p>
|
||||
|
||||
<p><strong>输出：</strong><span class="example-io">1</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><code>nums</code> 中严格递增的子数组有 <code>[3]</code>、<code>[3]</code>、<code>[3]</code> 以及 <code>[3]</code> 。</p>
|
||||
|
||||
<p><code>nums</code> 中严格递减的子数组有 <code>[3]</code>、<code>[3]</code>、<code>[3]</code> 以及 <code>[3]</code> 。</p>
|
||||
|
||||
<p>因此，返回 <code>1</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 3：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>输入：</strong><span class="example-io">nums = [3,2,1]</span></p>
|
||||
|
||||
<p><strong>输出：</strong><span class="example-io">3</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><code>nums</code> 中严格递增的子数组有 <code>[3]</code>、<code>[2]</code> 以及 <code>[1]</code> 。</p>
|
||||
|
||||
<p><code>nums</code> 中严格递减的子数组有 <code>[3]</code>、<code>[2]</code>、<code>[1]</code>、<code>[3,2]</code>、<code>[2,1]</code> 以及 <code>[3,2,1]</code> 。</p>
|
||||
|
||||
<p>因此，返回 <code>3</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 50</code></li>
|
||||
<li><code>1 <= nums[i] <= 50</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,55 @@
|
||||
<p>给你一个长度为 <code>n</code> 的整数数组 <code>nums</code> 和一个 <strong>正</strong> 整数 <code>k</code> 。</p>
|
||||
|
||||
<p>一个子序列的 <strong>能量</strong> 定义为子序列中 <strong>任意</strong> 两个元素的差值绝对值的 <strong>最小值</strong> 。</p>
|
||||
|
||||
<p>请你返回 <code>nums</code> 中长度 <strong>等于</strong> <code>k</code> 的 <strong>所有</strong> 子序列的 <strong>能量和</strong> 。</p>
|
||||
|
||||
<p>由于答案可能会很大，将答案对 <code>10<sup>9 </sup>+ 7</code> <strong>取余</strong> 后返回。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [1,2,3,4], k = 3</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>4</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><code>nums</code> 中总共有 4 个长度为 3 的子序列：<code>[1,2,3]</code> ，<code>[1,3,4]</code> ，<code>[1,2,4]</code> 和 <code>[2,3,4]</code> 。能量和为 <code>|2 - 3| + |3 - 4| + |2 - 1| + |3 - 4| = 4</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><span class="example-io"><b>输入：</b>nums = [2,2], k = 2</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>0</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><code>nums</code> 中唯一一个长度为 2 的子序列是 <code>[2,2]</code> 。能量和为 <code>|2 - 2| = 0</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">示例 3：</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>输入：</strong><span class="example-io">nums = [4,3,-1], k = 2</span></p>
|
||||
|
||||
<p><span class="example-io"><b>输出：</b>10</span></p>
|
||||
|
||||
<p><strong>解释：</strong></p>
|
||||
|
||||
<p><code>nums</code> 总共有 3 个长度为 2 的子序列：<code>[4,3]</code> ，<code>[4,-1]</code> 和 <code>[3,-1]</code> 。能量和为 <code>|4 - 3| + |4 - (-1)| + |3 - (-1)| = 10</code> 。</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>2 <= n == nums.length <= 50</code></li>
|
||||
<li><code>-10<sup>8</sup> <= nums[i] <= 10<sup>8</sup> </code></li>
|
||||
<li><code>2 <= k <= n</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,60 @@
|
||||
<p>给你一个字符串 <code>s</code> 和一个整数 <code>k</code> 。</p>
|
||||
|
||||
<p>定义函数 <code>distance(s<sub>1</sub>, s<sub>2</sub>)</code> ，用于衡量两个长度为 <code>n</code> 的字符串 <code>s<sub>1</sub></code> 和 <code>s<sub>2</sub></code> 之间的距离，即：</p>
|
||||
|
||||
<ul>
|
||||
<li>字符 <code>'a'</code> 到 <code>'z'</code> 按 <strong>循环 </strong>顺序排列，对于区间 <code>[0, n - 1]</code> 中的 <code>i</code> ，计算所有「 <code>s<sub>1</sub>[i]</code> 和 <code>s<sub>2</sub>[i]</code> 之间<strong> 最小距离</strong>」的 <strong>和 </strong>。</li>
|
||||
</ul>
|
||||
|
||||
<p>例如，<code>distance("ab", "cd") == 4</code> ，且 <code>distance("a", "z") == 1</code> 。</p>
|
||||
|
||||
<p>你可以对字符串 <code>s</code> 执行<strong> 任意次 </strong>操作。在每次操作中，可以将 <code>s</code> 中的一个字母 <strong>改变 </strong>为<strong> 任意 </strong>其他小写英文字母。</p>
|
||||
|
||||
<p>返回一个字符串，表示在执行一些操作后你可以得到的 <strong>字典序最小</strong> 的字符串 <code>t</code> ，且满足 <code>distance(s, t) <= k</code> 。</p>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong class="example">示例 1：</strong></p>
|
||||
|
||||
<pre>
|
||||
<strong>输入：</strong>s = "zbbz", k = 3
|
||||
<strong>输出：</strong>"aaaz"
|
||||
<strong>解释：</strong>在这个例子中，可以执行以下操作：
|
||||
将 s[0] 改为 'a' ，s 变为 "abbz" 。
|
||||
将 s[1] 改为 'a' ，s 变为 "aabz" 。
|
||||
将 s[2] 改为 'a' ，s 变为 "aaaz" 。
|
||||
"zbbz" 和 "aaaz" 之间的距离等于 k = 3 。
|
||||
可以证明 "aaaz" 是在任意次操作后能够得到的字典序最小的字符串。
|
||||
因此，答案是 "aaaz" 。
|
||||
</pre>
|
||||
|
||||
<p><strong class="example">示例 2：</strong></p>
|
||||
|
||||
<pre>
|
||||
<strong>输入：</strong>s = "xaxcd", k = 4
|
||||
<strong>输出：</strong>"aawcd"
|
||||
<strong>解释：</strong>在这个例子中，可以执行以下操作：
|
||||
将 s[0] 改为 'a' ，s 变为 "aaxcd" 。
|
||||
将 s[2] 改为 'w' ，s 变为 "aawcd" 。
|
||||
"xaxcd" 和 "aawcd" 之间的距离等于 k = 4 。
|
||||
可以证明 "aawcd" 是在任意次操作后能够得到的字典序最小的字符串。
|
||||
因此，答案是 "aawcd" 。
|
||||
</pre>
|
||||
|
||||
<p><strong class="example">示例 3：</strong></p>
|
||||
|
||||
<pre>
|
||||
<strong>输入：</strong>s = "lol", k = 0
|
||||
<strong>输出：</strong>"lol"
|
||||
<strong>解释：</strong>在这个例子中，k = 0，更改任何字符都会使得距离大于 0 。
|
||||
因此，答案是 "lol" 。</pre>
|
||||
|
||||
<p> </p>
|
||||
|
||||
<p><strong>提示：</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= s.length <= 100</code></li>
|
||||
<li><code>0 <= k <= 2000</code></li>
|
||||
<li><code>s</code> 只包含小写英文字母。</li>
|
||||
</ul>
|
||||
@@ -0,0 +1,38 @@
|
||||
<p>You are given a <span data-keyword="binary-array">binary array</span> <code>nums</code>.</p>
|
||||
|
||||
<p>We call a <span data-keyword="subarray-nonempty">subarray</span> <strong>alternating</strong> if <strong>no</strong> two <strong>adjacent</strong> elements in the subarray have the <strong>same</strong> value.</p>
|
||||
|
||||
<p>Return <em>the number of alternating subarrays in </em><code>nums</code>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [0,1,1,1]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">5</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The following subarrays are alternating: <code>[0]</code>, <code>[1]</code>, <code>[1]</code>, <code>[1]</code>, and <code>[0,1]</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [1,0,1,0]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">10</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>Every subarray of the array is alternating. There are 10 possible subarrays that we can choose.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>nums[i]</code> is either <code>0</code> or <code>1</code>.</li>
|
||||
</ul>
|
||||
@@ -0,0 +1,49 @@
|
||||
<p>You are given an integer array <code>nums</code> and a <strong>non-negative</strong> integer <code>k</code>. In one operation, you can increase or decrease any element by 1.</p>
|
||||
|
||||
<p>Return the <strong>minimum</strong> number of operations needed to make the <strong><span data-keyword="median-array">median</span></strong> of <code>nums</code> <em>equal</em> to <code>k</code>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [2,5,6,8,5], k = 4</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">2</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>We can subtract one from <code>nums[1]</code> and <code>nums[4]</code> to obtain <code>[2, 4, 6, 8, 4]</code>. The median of the resulting array is equal to <code>k</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [2,5,6,8,5], k = 7</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">3</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>We can add one to <code>nums[1]</code> twice and add one to <code>nums[2]</code> once to obtain <code>[2, 7, 7, 8, 5]</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 3:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3,4,5,6], k = 4</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">0</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The median of the array is already equal to <code>k</code>.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 2 * 10<sup>5</sup></code></li>
|
||||
<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>
|
||||
<li><code>1 <= k <= 10<sup>9</sup></code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,33 @@
|
||||
<p>An integer divisible by the <strong>sum</strong> of its digits is said to be a <strong>Harshad</strong> number. You are given an integer <code>x</code>. Return<em> the sum of the digits </em>of<em> </em><code>x</code><em> </em>if<em> </em><code>x</code><em> </em>is a <strong>Harshad</strong> number, otherwise, return<em> </em><code>-1</code><em>.</em></p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">x = 18</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">9</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The sum of digits of <code>x</code> is <code>9</code>. <code>18</code> is divisible by <code>9</code>. So <code>18</code> is a Harshad number and the answer is <code>9</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">x = 23</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">-1</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The sum of digits of <code>x</code> is <code>5</code>. <code>23</code> is not divisible by <code>5</code>. So <code>23</code> is not a Harshad number and the answer is <code>-1</code>.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= x <= 100</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,53 @@
|
||||
<p>There is an undirected weighted graph with <code>n</code> vertices labeled from <code>0</code> to <code>n - 1</code>.</p>
|
||||
|
||||
<p>You are given the integer <code>n</code> and an array <code>edges</code>, where <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>, w<sub>i</sub>]</code> indicates that there is an edge between vertices <code>u<sub>i</sub></code> and <code>v<sub>i</sub></code> with a weight of <code>w<sub>i</sub></code>.</p>
|
||||
|
||||
<p>A walk on a graph is a sequence of vertices and edges. The walk starts and ends with a vertex, and each edge connects the vertex that comes before it and the vertex that comes after it. It's important to note that a walk may visit the same edge or vertex more than once.</p>
|
||||
|
||||
<p>The <strong>cost</strong> of a walk starting at node <code>u</code> and ending at node <code>v</code> is defined as the bitwise <code>AND</code> of the weights of the edges traversed during the walk. In other words, if the sequence of edge weights encountered during the walk is <code>w<sub>0</sub>, w<sub>1</sub>, w<sub>2</sub>, ..., w<sub>k</sub></code>, then the cost is calculated as <code>w<sub>0</sub> & w<sub>1</sub> & w<sub>2</sub> & ... & w<sub>k</sub></code>, where <code>&</code> denotes the bitwise <code>AND</code> operator.</p>
|
||||
|
||||
<p>You are also given a 2D array <code>query</code>, where <code>query[i] = [s<sub>i</sub>, t<sub>i</sub>]</code>. For each query, you need to find the minimum cost of the walk starting at vertex <code>s<sub>i</sub></code> and ending at vertex <code>t<sub>i</sub></code>. If there exists no such walk, the answer is <code>-1</code>.</p>
|
||||
|
||||
<p>Return <em>the array </em><code>answer</code><em>, where </em><code>answer[i]</code><em> denotes the <strong>minimum</strong> cost of a walk for query </em><code>i</code>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">n = 5, edges = [[0,1,7],[1,3,7],[1,2,1]], query = [[0,3],[3,4]]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">[1,-1]</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
<img alt="" src="https://assets.leetcode.com/uploads/2024/01/31/q4_example1-1.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 351px; height: 141px;" />
|
||||
<p>To achieve the cost of 1 in the first query, we need to move on the following edges: <code>0->1</code> (weight 7), <code>1->2</code> (weight 1), <code>2->1</code> (weight 1), <code>1->3</code> (weight 7).</p>
|
||||
|
||||
<p>In the second query, there is no walk between nodes 3 and 4, so the answer is -1.</p>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
</div>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">n = 3, edges = [[0,2,7],[0,1,15],[1,2,6],[1,2,1]], query = [[1,2]]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">[0]</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
<img alt="" src="https://assets.leetcode.com/uploads/2024/01/31/q4_example2e.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 211px; height: 181px;" />
|
||||
<p>To achieve the cost of 0 in the first query, we need to move on the following edges: <code>1->2</code> (weight 1), <code>2->1</code> (weight 6), <code>1->2</code> (weight 1).</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= n <= 10<sup>5</sup></code></li>
|
||||
<li><code>0 <= edges.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>edges[i].length == 3</code></li>
|
||||
<li><code>0 <= u<sub>i</sub>, v<sub>i</sub> <= n - 1</code></li>
|
||||
<li><code>u<sub>i</sub> != v<sub>i</sub></code></li>
|
||||
<li><code>0 <= w<sub>i</sub> <= 10<sup>5</sup></code></li>
|
||||
<li><code>1 <= query.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>query[i].length == 2</code></li>
|
||||
<li><code>0 <= s<sub>i</sub>, t<sub>i</sub> <= n - 1</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,73 @@
|
||||
<p>You are given a binary array <code>possible</code> of length <code>n</code>.</p>
|
||||
|
||||
<p>Danielchandg and Bob are playing a game that consists of <code>n</code> levels. Some of the levels in the game are <strong>impossible</strong> to clear while others can <strong>always</strong> be cleared. In particular, if <code>possible[i] == 0</code>, then the <code>i<sup>th</sup></code> level is <strong>impossible</strong> to clear for <strong>both</strong> the players. A player gains <code>1</code> point on clearing a level and loses <code>1</code> point if the player fails to clear it.</p>
|
||||
|
||||
<p>At the start of the game, Danielchandg will play some levels in the <strong>given order</strong> starting from the <code>0<sup>th</sup></code> level, after which Bob will play for the rest of the levels.</p>
|
||||
|
||||
<p>Danielchandg wants to know the <strong>minimum</strong> number of levels he should play to gain more points than Bob, if both players play optimally to <strong>maximize</strong> their points.</p>
|
||||
|
||||
<p>Return <em>the <strong>minimum</strong> number of levels danielchandg should play to gain more points</em>. <em>If this is <strong>not</strong> possible, return</em> <code>-1</code>.</p>
|
||||
|
||||
<p><strong>Note</strong> that each player must play at least <code>1</code> level.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">possible = [1,0,1,0]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">1</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>Let's look at all the levels that Danielchandg can play up to:</p>
|
||||
|
||||
<ul>
|
||||
<li>If Danielchandg plays only level 0 and Bob plays the rest of the levels, Danielchandg has 1 point, while Bob has -1 + 1 - 1 = -1 point.</li>
|
||||
<li>If Danielchandg plays till level 1 and Bob plays the rest of the levels, Danielchandg has 1 - 1 = 0 points, while Bob has 1 - 1 = 0 points.</li>
|
||||
<li>If Danielchandg plays till level 2 and Bob plays the rest of the levels, Danielchandg has 1 - 1 + 1 = 1 point, while Bob has -1 point.</li>
|
||||
</ul>
|
||||
|
||||
<p>Danielchandg must play a minimum of 1 level to gain more points.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">possible = [1,1,1,1,1]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">3</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>Let's look at all the levels that Danielchandg can play up to:</p>
|
||||
|
||||
<ul>
|
||||
<li>If Danielchandg plays only level 0 and Bob plays the rest of the levels, Danielchandg has 1 point, while Bob has 4 points.</li>
|
||||
<li>If Danielchandg plays till level 1 and Bob plays the rest of the levels, Danielchandg has 2 points, while Bob has 3 points.</li>
|
||||
<li>If Danielchandg plays till level 2 and Bob plays the rest of the levels, Danielchandg has 3 points, while Bob has 2 points.</li>
|
||||
<li>If Danielchandg plays till level 3 and Bob plays the rest of the levels, Danielchandg has 4 points, while Bob has 1 point.</li>
|
||||
</ul>
|
||||
|
||||
<p>Danielchandg must play a minimum of 3 levels to gain more points.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 3:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">possible = [0,0]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">-1</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The only possible way is for both players to play 1 level each. Danielchandg plays level 0 and loses 1 point. Bob plays level 1 and loses 1 point. As both players have equal points, Danielchandg can't gain more points than Bob.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>2 <= n == possible.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>possible[i]</code> is either <code>0</code> or <code>1</code>.</li>
|
||||
</ul>
|
||||
@@ -0,0 +1,51 @@
|
||||
<p>You are given an array <code>nums</code> of <strong>non-negative</strong> integers and an integer <code>k</code>.</p>
|
||||
|
||||
<p>An array is called <strong>special</strong> if the bitwise <code>OR</code> of all of its elements is <strong>at least</strong> <code>k</code>.</p>
|
||||
|
||||
<p>Return <em>the length of the <strong>shortest</strong> <strong>special</strong> <strong>non-empty</strong> <span data-keyword="subarray-nonempty">subarray</span> of</em> <code>nums</code>, <em>or return</em> <code>-1</code> <em>if no special subarray exists</em>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3], k = 2</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">1</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The subarray <code>[3]</code> has <code>OR</code> value of <code>3</code>. Hence, we return <code>1</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [2,1,8], k = 10</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">3</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The subarray <code>[2,1,8]</code> has <code>OR</code> value of <code>11</code>. Hence, we return <code>3</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 3:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [1,2], k = 0</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">1</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The subarray <code>[1]</code> has <code>OR</code> value of <code>1</code>. Hence, we return <code>1</code>.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 50</code></li>
|
||||
<li><code>0 <= nums[i] <= 50</code></li>
|
||||
<li><code>0 <= k < 64</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,51 @@
|
||||
<p>You are given an array <code>nums</code> of <strong>non-negative</strong> integers and an integer <code>k</code>.</p>
|
||||
|
||||
<p>An array is called <strong>special</strong> if the bitwise <code>OR</code> of all of its elements is <strong>at least</strong> <code>k</code>.</p>
|
||||
|
||||
<p>Return <em>the length of the <strong>shortest</strong> <strong>special</strong> <strong>non-empty</strong> <span data-keyword="subarray-nonempty">subarray</span> of</em> <code>nums</code>, <em>or return</em> <code>-1</code> <em>if no special subarray exists</em>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3], k = 2</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">1</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The subarray <code>[3]</code> has <code>OR</code> value of <code>3</code>. Hence, we return <code>1</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [2,1,8], k = 10</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">3</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The subarray <code>[2,1,8]</code> has <code>OR</code> value of <code>11</code>. Hence, we return <code>3</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 3:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [1,2], k = 0</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">1</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The subarray <code>[1]</code> has <code>OR</code> value of <code>1</code>. Hence, we return <code>1</code>.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 2 * 10<sup>5</sup></code></li>
|
||||
<li><code>0 <= nums[i] <= 10<sup>9</sup></code></li>
|
||||
<li><code>0 <= k <= 10<sup>9</sup></code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,37 @@
|
||||
<p>You are given two integers <code>numBottles</code> and <code>numExchange</code>.</p>
|
||||
|
||||
<p><code>numBottles</code> represents the number of full water bottles that you initially have. In one operation, you can perform one of the following operations:</p>
|
||||
|
||||
<ul>
|
||||
<li>Drink any number of full water bottles turning them into empty bottles.</li>
|
||||
<li>Exchange <code>numExchange</code> empty bottles with one full water bottle. Then, increase <code>numExchange</code> by one.</li>
|
||||
</ul>
|
||||
|
||||
<p>Note that you cannot exchange multiple batches of empty bottles for the same value of <code>numExchange</code>. For example, if <code>numBottles == 3</code> and <code>numExchange == 1</code>, you cannot exchange <code>3</code> empty water bottles for <code>3</code> full bottles.</p>
|
||||
|
||||
<p>Return <em>the <strong>maximum</strong> number of water bottles you can drink</em>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
<img alt="" src="https://assets.leetcode.com/uploads/2024/01/28/exampleone1.png" style="width: 948px; height: 482px; padding: 10px; background: #fff; border-radius: .5rem;" />
|
||||
<pre>
|
||||
<strong>Input:</strong> numBottles = 13, numExchange = 6
|
||||
<strong>Output:</strong> 15
|
||||
<strong>Explanation:</strong> The table above shows the number of full water bottles, empty water bottles, the value of numExchange, and the number of bottles drunk.
|
||||
</pre>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
<img alt="" src="https://assets.leetcode.com/uploads/2024/01/28/example231.png" style="width: 990px; height: 642px; padding: 10px; background: #fff; border-radius: .5rem;" />
|
||||
<pre>
|
||||
<strong>Input:</strong> numBottles = 10, numExchange = 3
|
||||
<strong>Output:</strong> 13
|
||||
<strong>Explanation:</strong> The table above shows the number of full water bottles, empty water bottles, the value of numExchange, and the number of bottles drunk.
|
||||
</pre>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= numBottles <= 100 </code></li>
|
||||
<li><code>1 <= numExchange <= 100</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,48 @@
|
||||
<p>You are given a array <code>points</code> representing integer coordinates of some points on a 2D plane, where <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code>.</p>
|
||||
|
||||
<p>The distance between two points is defined as their <span data-keyword="manhattan-distance">Manhattan distance</span>.</p>
|
||||
|
||||
<p>Return <em>the <strong>minimum</strong> possible value for <strong>maximum</strong> distance between any two points by removing exactly one point</em>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">points = [[3,10],[5,15],[10,2],[4,4]]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">12</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The maximum distance after removing each point is the following:</p>
|
||||
|
||||
<ul>
|
||||
<li>After removing the 0<sup>th</sup> point the maximum distance is between points (5, 15) and (10, 2), which is <code>|5 - 10| + |15 - 2| = 18</code>.</li>
|
||||
<li>After removing the 1<sup>st</sup> point the maximum distance is between points (3, 10) and (10, 2), which is <code>|3 - 10| + |10 - 2| = 15</code>.</li>
|
||||
<li>After removing the 2<sup>nd</sup> point the maximum distance is between points (5, 15) and (4, 4), which is <code>|5 - 4| + |15 - 4| = 12</code>.</li>
|
||||
<li>After removing the 3<sup>rd</sup> point the maximum distance is between points (5, 15) and (10, 2), which is <code>|5 - 10| + |15 - 2| = 18</code>.</li>
|
||||
</ul>
|
||||
|
||||
<p>12 is the minimum possible maximum distance between any two points after removing exactly one point.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">points = [[1,1],[1,1],[1,1]]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">0</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>Removing any of the points results in the maximum distance between any two points of 0.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>3 <= points.length <= 10<sup>5</sup></code></li>
|
||||
<li><code>points[i].length == 2</code></li>
|
||||
<li><code>1 <= points[i][0], points[i][1] <= 10<sup>8</sup></code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,58 @@
|
||||
<p>You are given an array of integers <code>nums</code>. Return <em>the length of the <strong>longest</strong> <span data-keyword="subarray-nonempty">subarray</span> of </em><code>nums</code><em> which is either <strong><span data-keyword="strictly-increasing-array">strictly increasing</span></strong> or <strong><span data-keyword="strictly-decreasing-array">strictly decreasing</span></strong></em>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [1,4,3,3,2]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">2</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The strictly increasing subarrays of <code>nums</code> are <code>[1]</code>, <code>[2]</code>, <code>[3]</code>, <code>[3]</code>, <code>[4]</code>, and <code>[1,4]</code>.</p>
|
||||
|
||||
<p>The strictly decreasing subarrays of <code>nums</code> are <code>[1]</code>, <code>[2]</code>, <code>[3]</code>, <code>[3]</code>, <code>[4]</code>, <code>[3,2]</code>, and <code>[4,3]</code>.</p>
|
||||
|
||||
<p>Hence, we return <code>2</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [3,3,3,3]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">1</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The strictly increasing subarrays of <code>nums</code> are <code>[3]</code>, <code>[3]</code>, <code>[3]</code>, and <code>[3]</code>.</p>
|
||||
|
||||
<p>The strictly decreasing subarrays of <code>nums</code> are <code>[3]</code>, <code>[3]</code>, <code>[3]</code>, and <code>[3]</code>.</p>
|
||||
|
||||
<p>Hence, we return <code>1</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 3:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [3,2,1]</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">3</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The strictly increasing subarrays of <code>nums</code> are <code>[3]</code>, <code>[2]</code>, and <code>[1]</code>.</p>
|
||||
|
||||
<p>The strictly decreasing subarrays of <code>nums</code> are <code>[3]</code>, <code>[2]</code>, <code>[1]</code>, <code>[3,2]</code>, <code>[2,1]</code>, and <code>[3,2,1]</code>.</p>
|
||||
|
||||
<p>Hence, we return <code>3</code>.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= nums.length <= 50</code></li>
|
||||
<li><code>1 <= nums[i] <= 50</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,53 @@
|
||||
<p>You are given an integer array <code>nums</code> of length <code>n</code>, and a <strong>positive</strong> integer <code>k</code>.</p>
|
||||
|
||||
<p>The <strong>power</strong> of a <span data-keyword="subsequence-array">subsequence</span> is defined as the <strong>minimum</strong> absolute difference between <strong>any</strong> two elements in the subsequence.</p>
|
||||
|
||||
<p>Return <em>the <strong>sum</strong> of <strong>powers</strong> of <strong>all</strong> subsequences of </em><code>nums</code><em> which have length</em> <strong><em>equal to</em></strong> <code>k</code>.</p>
|
||||
|
||||
<p>Since the answer may be large, return it <strong>modulo</strong> <code>10<sup>9 </sup>+ 7</code>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3,4], k = 3</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">4</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>There are 4 subsequences in <code>nums</code> which have length 3: <code>[1,2,3]</code>, <code>[1,3,4]</code>, <code>[1,2,4]</code>, and <code>[2,3,4]</code>. The sum of powers is <code>|2 - 3| + |3 - 4| + |2 - 1| + |3 - 4| = 4</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [2,2], k = 2</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">0</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The only subsequence in <code>nums</code> which has length 2 is <code>[2,2]</code>. The sum of powers is <code>|2 - 2| = 0</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 3:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">nums = [4,3,-1], k = 2</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">10</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>There are 3 subsequences in <code>nums</code> which have length 2: <code>[4,3]</code>, <code>[4,-1]</code>, and <code>[3,-1]</code>. The sum of powers is <code>|4 - 3| + |4 - (-1)| + |3 - (-1)| = 10</code>.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>2 <= n == nums.length <= 50</code></li>
|
||||
<li><code>-10<sup>8</sup> <= nums[i] <= 10<sup>8</sup> </code></li>
|
||||
<li><code>2 <= k <= n</code></li>
|
||||
</ul>
|
||||
@@ -0,0 +1,59 @@
|
||||
<p>You are given a string <code>s</code> and an integer <code>k</code>.</p>
|
||||
|
||||
<p>Define a function <code>distance(s<sub>1</sub>, s<sub>2</sub>)</code> between two strings <code>s<sub>1</sub></code> and <code>s<sub>2</sub></code> of the same length <code>n</code> as:</p>
|
||||
|
||||
<ul>
|
||||
<li>The<strong> sum</strong> of the <strong>minimum distance</strong> between <code>s<sub>1</sub>[i]</code> and <code>s<sub>2</sub>[i]</code> when the characters from <code>'a'</code> to <code>'z'</code> are placed in a <strong>cyclic</strong> order, for all <code>i</code> in the range <code>[0, n - 1]</code>.</li>
|
||||
</ul>
|
||||
|
||||
<p>For example, <code>distance("ab", "cd") == 4</code>, and <code>distance("a", "z") == 1</code>.</p>
|
||||
|
||||
<p>You can <strong>change</strong> any letter of <code>s</code> to <strong>any</strong> other lowercase English letter, <strong>any</strong> number of times.</p>
|
||||
|
||||
<p>Return a string denoting the <strong><span data-keyword="lexicographically-smaller-string">lexicographically smallest</span></strong> string <code>t</code> you can get after some changes, such that <code>distance(s, t) <= k</code>.</p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">s = "zbbz", k = 3</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">"aaaz"</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>Change <code>s</code> to <code>"aaaz"</code>. The distance between <code>"zbbz"</code> and <code>"aaaz"</code> is equal to <code>k = 3</code>.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">s = "xaxcd", k = 4</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">"aawcd"</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>The distance between "xaxcd" and "aawcd" is equal to k = 4.</p>
|
||||
</div>
|
||||
|
||||
<p><strong class="example">Example 3:</strong></p>
|
||||
|
||||
<div class="example-block">
|
||||
<p><strong>Input:</strong> <span class="example-io">s = "lol", k = 0</span></p>
|
||||
|
||||
<p><strong>Output:</strong> <span class="example-io">"lol"</span></p>
|
||||
|
||||
<p><strong>Explanation:</strong></p>
|
||||
|
||||
<p>It's impossible to change any character as <code>k = 0</code>.</p>
|
||||
</div>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Constraints:</strong></p>
|
||||
|
||||
<ul>
|
||||
<li><code>1 <= s.length <= 100</code></li>
|
||||
<li><code>0 <= k <= 2000</code></li>
|
||||
<li><code>s</code> consists only of lowercase English letters.</li>
|
||||
</ul>
|
||||
Reference in New Issue
Block a user