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算法题(国外版)/substring-with-concatenation-of-all-words.html
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算法题(国外版)/substring-with-concatenation-of-all-words.html
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<p>You are given a string <code>s</code> and an array of strings <code>words</code> of <strong>the same length</strong>. Return all starting indices of substring(s) in <code>s</code> that is a concatenation of each word in <code>words</code> <strong>exactly once</strong>, <strong>in any order</strong>, and <strong>without any intervening characters</strong>.</p>
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<p>You can return the answer in <strong>any order</strong>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> s = "barfoothefoobarman", words = ["foo","bar"]
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<strong>Output:</strong> [0,9]
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<strong>Explanation:</strong> Substrings starting at index 0 and 9 are "barfoo" and "foobar" respectively.
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The output order does not matter, returning [9,0] is fine too.
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> s = "wordgoodgoodgoodbestword", words = ["word","good","best","word"]
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<strong>Output:</strong> []
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</pre>
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<p><strong>Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> s = "barfoofoobarthefoobarman", words = ["bar","foo","the"]
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<strong>Output:</strong> [6,9,12]
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= s.length <= 10<sup>4</sup></code></li>
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<li><code>s</code> consists of lower-case English letters.</li>
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<li><code>1 <= words.length <= 5000</code></li>
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<li><code>1 <= words[i].length <= 30</code></li>
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<li><code>words[i]</code> consists of lower-case English letters.</li>
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</ul>
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