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<p>Given an integer array <code>nums</code> sorted in <strong>non-decreasing</strong> order, return <em>an array of <strong>the squares of each number</strong> sorted in non-decreasing order</em>.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [-4,-1,0,3,10]
<strong>Output:</strong> [0,1,9,16,100]
<strong>Explanation:</strong> After squaring, the array becomes [16,1,0,9,100].
After sorting, it becomes [0,1,9,16,100].
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [-7,-3,2,3,11]
<strong>Output:</strong> [4,9,9,49,121]
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code><span>1 &lt;= nums.length &lt;= </span>10<sup>4</sup></code></li>
<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>
<li><code>nums</code> is sorted in <strong>non-decreasing</strong> order.</li>
</ul>
<p>&nbsp;</p>
<strong>Follow up:</strong> Squaring each element and sorting the new array is very trivial, could you find an <code>O(n)</code> solution using a different approach?