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算法题(国外版)/sort-characters-by-frequency.html
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算法题(国外版)/sort-characters-by-frequency.html
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<p>Given a string <code>s</code>, sort it in <strong>decreasing order</strong> based on the <strong>frequency</strong> of the characters. The <strong>frequency</strong> of a character is the number of times it appears in the string.</p>
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<p>Return <em>the sorted string</em>. If there are multiple answers, return <em>any of them</em>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> s = "tree"
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<strong>Output:</strong> "eert"
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<strong>Explanation:</strong> 'e' appears twice while 'r' and 't' both appear once.
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So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also a valid answer.
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> s = "cccaaa"
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<strong>Output:</strong> "aaaccc"
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<strong>Explanation:</strong> Both 'c' and 'a' appear three times, so both "cccaaa" and "aaaccc" are valid answers.
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Note that "cacaca" is incorrect, as the same characters must be together.
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</pre>
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<p><strong>Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> s = "Aabb"
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<strong>Output:</strong> "bbAa"
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<strong>Explanation:</strong> "bbaA" is also a valid answer, but "Aabb" is incorrect.
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Note that 'A' and 'a' are treated as two different characters.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= s.length <= 5 * 10<sup>5</sup></code></li>
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<li><code>s</code> consists of uppercase and lowercase English letters and digits.</li>
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</ul>
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