coder-xiaomo/leetcode-problemset
1
0
Fork 0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-11-04 11:43:12 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee

国外版

Browse Source
This commit is contained in:
小墨
2022-03-27 18:52:06 +08:00
parent 4a83e940d3
commit 44cb2b9989
3970 changed files with 620 additions and 621 deletions
Download Patch File Download Diff File Expand all files Collapse all files

52
算法题（国外版）/minimum-cost-to-reach-destination-in-time.html Normal file
View File

@@ -0,0 +1,52 @@
<p>There is a country of <code>n</code> cities numbered from <code>0</code> to <code>n - 1</code> where <strong>all the cities are connected</strong> by bi-directional roads. The roads are represented as a 2D integer array <code>edges</code> where <code>edges[i] = [x<sub>i</sub>, y<sub>i</sub>, time<sub>i</sub>]</code> denotes a road between cities <code>x<sub>i</sub></code> and <code>y<sub>i</sub></code> that takes <code>time<sub>i</sub></code> minutes to travel. There may be multiple roads of differing travel times connecting the same two cities, but no road connects a city to itself.</p>
<p>Each time you pass through a city, you must pay a passing fee. This is represented as a <strong>0-indexed</strong> integer array <code>passingFees</code> of length <code>n</code> where <code>passingFees[j]</code> is the amount of dollars you must pay when you pass through city <code>j</code>.</p>
<p>In the beginning, you are at city <code>0</code> and want to reach city <code>n - 1</code> in <code>maxTime</code><strong> minutes or less</strong>. The <strong>cost</strong> of your journey is the <strong>summation of passing fees</strong> for each city that you passed through at some moment of your journey (<strong>including</strong> the source and destination cities).</p>
<p>Given <code>maxTime</code>, <code>edges</code>, and <code>passingFees</code>, return <em>the <strong>minimum cost</strong> to complete your journey, or </em><code>-1</code><em> if you cannot complete it within </em><code>maxTime</code><em> minutes</em>.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<p><img alt="" src="https://assets.leetcode.com/uploads/2021/06/04/leetgraph1-1.png" style="width: 371px; height: 171px;" /></p>
<pre>
<strong>Input:</strong> maxTime = 30, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]
<strong>Output:</strong> 11
<strong>Explanation:</strong> The path to take is 0 -&gt; 1 -&gt; 2 -&gt; 5, which takes 30 minutes and has $11 worth of passing fees.
</pre>
<p><strong>Example 2:</strong></p>
<p><strong><img alt="" src="https://assets.leetcode.com/uploads/2021/06/04/copy-of-leetgraph1-1.png" style="width: 371px; height: 171px;" /></strong></p>
<pre>
<strong>Input:</strong> maxTime = 29, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]
<strong>Output:</strong> 48
<strong>Explanation:</strong> The path to take is 0 -&gt; 3 -&gt; 4 -&gt; 5, which takes 26 minutes and has $48 worth of passing fees.
You cannot take path 0 -&gt; 1 -&gt; 2 -&gt; 5 since it would take too long.
</pre>
<p><strong>Example 3:</strong></p>
<pre>
<strong>Input:</strong> maxTime = 25, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]
<strong>Output:</strong> -1
<strong>Explanation:</strong> There is no way to reach city 5 from city 0 within 25 minutes.
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= maxTime &lt;= 1000</code></li>
<li><code>n == passingFees.length</code></li>
<li><code>2 &lt;= n &lt;= 1000</code></li>
<li><code>n - 1 &lt;= edges.length &lt;= 1000</code></li>
<li><code>0 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= n - 1</code></li>
<li><code>1 &lt;= time<sub>i</sub> &lt;= 1000</code></li>
<li><code>1 &lt;= passingFees[j] &lt;= 1000</code>&nbsp;</li>
<li>The graph may contain multiple edges between two nodes.</li>
<li>The graph does not contain self loops.</li>
</ul>