国外版

算法题（国外版）/exchange-seats.html

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+<p>Table: <code>Seat</code></p>
+
+<pre>
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| id          | int     |
+| name        | varchar |
++-------------+---------+
+id is the primary key column for this table.
+Each row of this table indicates the name and the ID of a student.
+id is a continuous increment.
+</pre>
+
+<p>&nbsp;</p>
+
+<p>Write an SQL query to swap the seat id of every two consecutive students. If the number of students is odd, the id of the last student is not swapped.</p>
+
+<p>Return the result table ordered by <code>id</code> <strong>in ascending order</strong>.</p>
+
+<p>The query result format is in the following example.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> 
+Seat table:
++----+---------+
+| id | student |
++----+---------+
+| 1  | Abbot   |
+| 2  | Doris   |
+| 3  | Emerson |
+| 4  | Green   |
+| 5  | Jeames  |
++----+---------+
+<strong>Output:</strong> 
++----+---------+
+| id | student |
++----+---------+
+| 1  | Doris   |
+| 2  | Abbot   |
+| 3  | Green   |
+| 4  | Emerson |
+| 5  | Jeames  |
++----+---------+
+<strong>Explanation:</strong> 
+Note that if the number of students is odd, there is no need to change the last one&#39;s seat.
+</pre>