国外版

算法题（国外版）/custom-sort-string.html

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+<p>You are given two strings order and s. All the words of <code>order</code> are <strong>unique</strong> and were sorted in some custom order previously.</p>
+
+<p>Permute the characters of <code>s</code> so that they match the order that <code>order</code> was sorted. More specifically, if a character <code>x</code> occurs before a character <code>y</code> in <code>order</code>, then <code>x</code> should occur before <code>y</code> in the permuted string.</p>
+
+<p>Return <em>any permutation of </em><code>s</code><em> that satisfies this property</em>.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> order = &quot;cba&quot;, s = &quot;abcd&quot;
+<strong>Output:</strong> &quot;cbad&quot;
+<strong>Explanation:</strong> 
+&quot;a&quot;, &quot;b&quot;, &quot;c&quot; appear in order, so the order of &quot;a&quot;, &quot;b&quot;, &quot;c&quot; should be &quot;c&quot;, &quot;b&quot;, and &quot;a&quot;. 
+Since &quot;d&quot; does not appear in order, it can be at any position in the returned string. &quot;dcba&quot;, &quot;cdba&quot;, &quot;cbda&quot; are also valid outputs.
+</pre>
+
+<p><strong>Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> order = &quot;cbafg&quot;, s = &quot;abcd&quot;
+<strong>Output:</strong> &quot;cbad&quot;
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= order.length &lt;= 26</code></li>
+	<li><code>1 &lt;= s.length &lt;= 200</code></li>
+	<li><code>order</code> and <code>s</code> consist of lowercase English letters.</li>
+	<li>All the characters of <code>order</code> are <strong>unique</strong>.</li>
+</ul>