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leetcode/problem/minimize-maximum-of-array.html

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+<p>You are given a <strong>0-indexed</strong> array <code>nums</code> comprising of <code>n</code> non-negative integers.</p>
+
+<p>In one operation, you must:</p>
+
+<ul>
+	<li>Choose an integer <code>i</code> such that <code>1 &lt;= i &lt; n</code> and <code>nums[i] &gt; 0</code>.</li>
+	<li>Decrease <code>nums[i]</code> by 1.</li>
+	<li>Increase <code>nums[i - 1]</code> by 1.</li>
+</ul>
+
+<p>Return<em> the <strong>minimum</strong> possible value of the <strong>maximum</strong> integer of </em><code>nums</code><em> after performing <strong>any</strong> number of operations</em>.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [3,7,1,6]
+<strong>Output:</strong> 5
+<strong>Explanation:</strong>
+One set of optimal operations is as follows:
+1. Choose i = 1, and nums becomes [4,6,1,6].
+2. Choose i = 3, and nums becomes [4,6,2,5].
+3. Choose i = 1, and nums becomes [5,5,2,5].
+The maximum integer of nums is 5. It can be shown that the maximum number cannot be less than 5.
+Therefore, we return 5.
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [10,1]
+<strong>Output:</strong> 10
+<strong>Explanation:</strong>
+It is optimal to leave nums as is, and since 10 is the maximum value, we return 10.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>n == nums.length</code></li>
+	<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>
+	<li><code>0 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
+</ul>