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小墨
2023-12-09 19:57:46 +08:00
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leetcode-cn/originData/minimum-operations-to-maximize-last-elements-in-arrays.json
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@@ -149,7 +149,7 @@
"__typename": "CodeSnippetNode"
}
],
"stats": "{\"totalAccepted\": \"3.8K\", \"totalSubmission\": \"8.2K\", \"totalAcceptedRaw\": 3817, \"totalSubmissionRaw\": 8154, \"acRate\": \"46.8%\"}",
"stats": "{\"totalAccepted\": \"3.8K\", \"totalSubmission\": \"8.2K\", \"totalAcceptedRaw\": 3818, \"totalSubmissionRaw\": 8155, \"acRate\": \"46.8%\"}",
"hints": [
"Consider how to calculate the minimum number of operations when <code>nums1[n - 1]</code> and <code>nums2[n - 1]</code> are fixed (they are not swapped).",
"For each index <code>i</code>, there are only <code>3</code> possibilities: <ul>\r\n<li><code>nums1[i] <= nums1[n - 1] && nums2[i] <= nums2[n - 1]</code>. We don't need to swap them.</li>\r\n<li><code>nums1[i] <= nums2[n - 1] && nums2[i] <= nums1[n - 1]</code>. We have to swap them.</li>\r\n<li>Otherwise, there is no solution.</li>\r\n</ul>",