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leetcode/problem/double-modular-exponentiation.html
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<p>You are given a <strong>0-indexed</strong> 2D array <code>variables</code> where <code>variables[i] = [a<sub>i</sub>, b<sub>i</sub>, c<sub>i,</sub> m<sub>i</sub>]</code>, and an integer <code>target</code>.</p>
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<p>An index <code>i</code> is <strong>good</strong> if the following formula holds:</p>
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<ul>
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<li><code>0 <= i < variables.length</code></li>
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<li><code>((a<sub>i</sub><sup>b<sub>i</sub></sup> % 10)<sup>c<sub>i</sub></sup>) % m<sub>i</sub> == target</code></li>
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</ul>
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<p>Return <em>an array consisting of <strong>good</strong> indices in <strong>any order</strong></em>.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> variables = [[2,3,3,10],[3,3,3,1],[6,1,1,4]], target = 2
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<strong>Output:</strong> [0,2]
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<strong>Explanation:</strong> For each index i in the variables array:
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1) For the index 0, variables[0] = [2,3,3,10], (2<sup>3</sup> % 10)<sup>3</sup> % 10 = 2.
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2) For the index 1, variables[1] = [3,3,3,1], (3<sup>3</sup> % 10)<sup>3</sup> % 1 = 0.
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3) For the index 2, variables[2] = [6,1,1,4], (6<sup>1</sup> % 10)<sup>1</sup> % 4 = 2.
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Therefore we return [0,2] as the answer.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> variables = [[39,3,1000,1000]], target = 17
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<strong>Output:</strong> []
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<strong>Explanation:</strong> For each index i in the variables array:
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1) For the index 0, variables[0] = [39,3,1000,1000], (39<sup>3</sup> % 10)<sup>1000</sup> % 1000 = 1.
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Therefore we return [] as the answer.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= variables.length <= 100</code></li>
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<li><code>variables[i] == [a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>, m<sub>i</sub>]</code></li>
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<li><code>1 <= a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>, m<sub>i</sub> <= 10<sup>3</sup></code></li>
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<li><code><font face="monospace">0 <= target <= 10<sup>3</sup></font></code></li>
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</ul>
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