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leetcode-cn/problem (English)/计算字符串的数字和(English) [calculate-digit-sum-of-a-string].html
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@@ -16,13 +16,13 @@
<pre>
<strong>Input:</strong> s = &quot;11111222223&quot;, k = 3
<strong>Output:</strong> &quot;135&quot;
<strong>Explanation:</strong>
<strong>Explanation:</strong>
- For the first round, we divide s into groups of size 3: &quot;111&quot;, &quot;112&quot;, &quot;222&quot;, and &quot;23&quot;.
​​​​​Then we calculate the digit sum of each group: 1 + 1 + 1 = 3, 1 + 1 + 2 = 4, 2 + 2 + 2 = 6, and 2 + 3 = 5.
Then we calculate the digit sum of each group: 1 + 1 + 1 = 3, 1 + 1 + 2 = 4, 2 + 2 + 2 = 6, and 2 + 3 = 5.
&nbsp; So, s becomes &quot;3&quot; + &quot;4&quot; + &quot;6&quot; + &quot;5&quot; = &quot;3465&quot; after the first round.
- For the second round, we divide s into &quot;346&quot; and &quot;5&quot;.
&nbsp; Then we calculate the digit sum of each group: 3 + 4 + 6 = 13, 5 = 5.
&nbsp; So, s becomes &quot;13&quot; + &quot;5&quot; = &quot;135&quot; after second round.
&nbsp; Then we calculate the digit sum of each group: 3 + 4 + 6 = 13, 5 = 5.
&nbsp; So, s becomes &quot;13&quot; + &quot;5&quot; = &quot;135&quot; after second round.
Now, s.length &lt;= k, so we return &quot;135&quot; as the answer.
</pre>
@@ -31,9 +31,9 @@ Now, s.length &lt;= k, so we return &quot;135&quot; as the answer.
<pre>
<strong>Input:</strong> s = &quot;00000000&quot;, k = 3
<strong>Output:</strong> &quot;000&quot;
<strong>Explanation:</strong>
<strong>Explanation:</strong>
We divide s into &quot;000&quot;, &quot;000&quot;, and &quot;00&quot;.
Then we calculate the digit sum of each group: 0 + 0 + 0 = 0, 0 + 0 + 0 = 0, and 0 + 0 = 0.
Then we calculate the digit sum of each group: 0 + 0 + 0 = 0, 0 + 0 + 0 = 0, and 0 + 0 = 0.
s becomes &quot;0&quot; + &quot;0&quot; + &quot;0&quot; = &quot;000&quot;, whose length is equal to k, so we return &quot;000&quot;.
</pre>