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leetcode-cn/problem (English)/有时间限制的 Promise 对象(English) [promise-time-limit].html
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@@ -11,10 +11,10 @@
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong>
fn = async (n) =&gt; {
&nbsp; await new Promise(res =&gt; setTimeout(res, 100));
&nbsp; return n * n;
<strong>Input:</strong>
fn = async (n) =&gt; {
&nbsp; await new Promise(res =&gt; setTimeout(res, 100));
&nbsp; return n * n;
}
inputs = [5]
t = 50
@@ -37,10 +37,10 @@ The provided function is set to resolve after 100ms. However, the time limit is
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong>
fn = async (n) =&gt; {
&nbsp; await new Promise(res =&gt; setTimeout(res, 100));
&nbsp; return n * n;
<strong>Input:</strong>
fn = async (n) =&gt; {
&nbsp; await new Promise(res =&gt; setTimeout(res, 100));
&nbsp; return n * n;
}
inputs = [5]
t = 150
@@ -52,23 +52,23 @@ The function resolved 5 * 5 = 25 at t=100ms. The time limit is never reached.
<p><strong class="example">Example 3:</strong></p>
<pre>
<strong>Input:</strong>
fn = async (a, b) =&gt; {
&nbsp; await new Promise(res =&gt; setTimeout(res, 120));
&nbsp; return a + b;
<strong>Input:</strong>
fn = async (a, b) =&gt; {
&nbsp; await new Promise(res =&gt; setTimeout(res, 120));
&nbsp; return a + b;
}
inputs = [5,10]
t = 150
<strong>Output:</strong> {&quot;resolved&quot;:15,&quot;time&quot;:120}
<strong>Explanation:</strong>
​​​​The function resolved 5 + 10 = 15 at t=120ms. The time limit is never reached.
The function resolved 5 + 10 = 15 at t=120ms. The time limit is never reached.
</pre>
<p><strong class="example">Example 4:</strong></p>
<pre>
<strong>Input:</strong>
fn = async () =&gt; {
<strong>Input:</strong>
fn = async () =&gt; {
&nbsp; throw &quot;Error&quot;;
}
inputs = []