mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-09-06 16:01:41 +08:00
移除零宽空格
This commit is contained in:
@@ -7,9 +7,9 @@
|
||||
"boundTopicId": 481396,
|
||||
"title": "Minimum Deletions to Make String Balanced",
|
||||
"titleSlug": "minimum-deletions-to-make-string-balanced",
|
||||
"content": "<p>You are given a string <code>s</code> consisting only of characters <code>'a'</code> and <code>'b'</code>.</p>\n\n<p>You can delete any number of characters in <code>s</code> to make <code>s</code> <strong>balanced</strong>. <code>s</code> is <strong>balanced</strong> if there is no pair of indices <code>(i,j)</code> such that <code>i < j</code> and <code>s[i] = 'b'</code> and <code>s[j]= 'a'</code>.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of deletions needed to make </em><code>s</code><em> <strong>balanced</strong></em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "aababbab"\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> You can either:\nDelete the characters at 0-indexed positions 2 and 6 ("aa<u>b</u>abb<u>a</u>b" -> "aaabbb"), or\nDelete the characters at 0-indexed positions 3 and 6 ("aab<u>a</u>bb<u>a</u>b" -> "aabbbb").\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "bbaaaaabb"\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The only solution is to delete the first two characters.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> is <code>'a'</code> or <code>'b'</code>.</li>\n</ul>\n",
|
||||
"content": "<p>You are given a string <code>s</code> consisting only of characters <code>'a'</code> and <code>'b'</code>.</p>\n\n<p>You can delete any number of characters in <code>s</code> to make <code>s</code> <strong>balanced</strong>. <code>s</code> is <strong>balanced</strong> if there is no pair of indices <code>(i,j)</code> such that <code>i < j</code> and <code>s[i] = 'b'</code> and <code>s[j]= 'a'</code>.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of deletions needed to make </em><code>s</code><em> <strong>balanced</strong></em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "aababbab"\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> You can either:\nDelete the characters at 0-indexed positions 2 and 6 ("aa<u>b</u>abb<u>a</u>b" -> "aaabbb"), or\nDelete the characters at 0-indexed positions 3 and 6 ("aab<u>a</u>bb<u>a</u>b" -> "aabbbb").\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "bbaaaaabb"\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The only solution is to delete the first two characters.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> is <code>'a'</code> or <code>'b'</code>.</li>\n</ul>\n",
|
||||
"translatedTitle": "使字符串平衡的最少删除次数",
|
||||
"translatedContent": "<p>给你一个字符串 <code>s</code> ,它仅包含字符 <code>'a'</code> 和 <code>'b'</code> 。</p>\n\n<p>你可以删除 <code>s</code> 中任意数目的字符,使得 <code>s</code> <strong>平衡</strong> 。当不存在下标对 <code>(i,j)</code> 满足 <code>i < j</code> ,且 <code>s[i] = 'b'</code> 的同时 <code>s[j]= 'a'</code> ,此时认为 <code>s</code> 是 <strong>平衡 </strong>的。</p>\n\n<p>请你返回使 <code>s</code> <strong>平衡</strong> 的 <strong>最少</strong> 删除次数。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<b>输入:</b>s = \"aababbab\"\n<b>输出:</b>2\n<b>解释:</b>你可以选择以下任意一种方案:\n下标从 0 开始,删除第 2 和第 6 个字符(\"aa<strong>b</strong>abb<strong>a</strong>b\" -> \"aaabbb\"),\n下标从 0 开始,删除第 3 和第 6 个字符(\"aab<strong>a</strong>bb<strong>a</strong>b\" -> \"aabbbb\")。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<b>输入:</b>s = \"bbaaaaabb\"\n<b>输出:</b>2\n<b>解释:</b>唯一的最优解是删除最前面两个字符。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> 要么是 <code>'a'</code> 要么是 <code>'b'</code><strong> </strong>。</li>\n</ul>\n",
|
||||
"translatedContent": "<p>给你一个字符串 <code>s</code> ,它仅包含字符 <code>'a'</code> 和 <code>'b'</code> 。</p>\n\n<p>你可以删除 <code>s</code> 中任意数目的字符,使得 <code>s</code> <strong>平衡</strong> 。当不存在下标对 <code>(i,j)</code> 满足 <code>i < j</code> ,且 <code>s[i] = 'b'</code> 的同时 <code>s[j]= 'a'</code> ,此时认为 <code>s</code> 是 <strong>平衡 </strong>的。</p>\n\n<p>请你返回使 <code>s</code> <strong>平衡</strong> 的 <strong>最少</strong> 删除次数。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<b>输入:</b>s = \"aababbab\"\n<b>输出:</b>2\n<b>解释:</b>你可以选择以下任意一种方案:\n下标从 0 开始,删除第 2 和第 6 个字符(\"aa<strong>b</strong>abb<strong>a</strong>b\" -> \"aaabbb\"),\n下标从 0 开始,删除第 3 和第 6 个字符(\"aab<strong>a</strong>bb<strong>a</strong>b\" -> \"aabbbb\")。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<b>输入:</b>s = \"bbaaaaabb\"\n<b>输出:</b>2\n<b>解释:</b>唯一的最优解是删除最前面两个字符。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> 要么是 <code>'a'</code> 要么是 <code>'b'</code><strong> </strong>。</li>\n</ul>\n",
|
||||
"isPaidOnly": false,
|
||||
"difficulty": "Medium",
|
||||
"likes": 199,
|
||||
|
Reference in New Issue
Block a user