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leetcode/originData/minimum-initial-energy-to-finish-tasks.json

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             "title": "Minimum Initial Energy to Finish Tasks",
             "titleSlug": "minimum-initial-energy-to-finish-tasks",
-            "content": "<p>You are given an array <code>tasks</code> where <code>tasks[i] = [actual<sub>i</sub>, minimum<sub>i</sub>]</code>:</p>\n\n<ul>\n\t<li><code>actual<sub>i</sub></code> is the actual amount of energy you <strong>spend to finish</strong> the <code>i<sup>th</sup></code> task.</li>\n\t<li><code>minimum<sub>i</sub></code> is the minimum amount of energy you <strong>require to begin</strong> the <code>i<sup>th</sup></code> task.</li>\n</ul>\n\n<p>For example, if the task is <code>[10, 12]</code> and your current energy is <code>11</code>, you cannot start this task. However, if your current energy is <code>13</code>, you can complete this task, and your energy will be <code>3</code> after finishing it.</p>\n\n<p>You can finish the tasks in <strong>any order</strong> you like.</p>\n\n<p>Return <em>the <strong>minimum</strong> initial amount of energy you will need</em> <em>to finish all the tasks</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [[1,2],[2,4],[4,8]]\n<strong>Output:</strong> 8\n<strong>Explanation:</strong>\nStarting with 8 energy, we finish the tasks in the following order:\n    - 3rd task. Now energy = 8 - 4 = 4.\n    - 2nd task. Now energy = 4 - 2 = 2.\n    - 1st task. Now energy = 2 - 1 = 1.\nNotice that even though we have leftover energy, starting with 7 energy does not work because we cannot do the 3rd task.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [[1,3],[2,4],[10,11],[10,12],[8,9]]\n<strong>Output:</strong> 32\n<strong>Explanation:</strong>\nStarting with 32 energy, we finish the tasks in the following order:\n    - 1st task. Now energy = 32 - 1 = 31.\n    - 2nd task. Now energy = 31 - 2 = 29.\n    - 3rd task. Now energy = 29 - 10 = 19.\n    - 4th task. Now energy = 19 - 10 = 9.\n    - 5th task. Now energy = 9 - 8 = 1.</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [[1,7],[2,8],[3,9],[4,10],[5,11],[6,12]]\n<strong>Output:</strong> 27\n<strong>Explanation:</strong>\nStarting with 27 energy, we finish the tasks in the following order:\n    - 5th task. Now energy = 27 - 5 = 22.\n    - 2nd task. Now energy = 22 - 2 = 20.\n    - 3rd task. Now energy = 20 - 3 = 17.\n    - 1st task. Now energy = 17 - 1 = 16.\n    - 4th task. Now energy = 16 - 4 = 12.\n    - 6th task. Now energy = 12 - 6 = 6.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= tasks.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= actual<sub>​i</sub>&nbsp;&lt;= minimum<sub>i</sub>&nbsp;&lt;= 10<sup>4</sup></code></li>\n</ul>\n",
+            "content": "<p>You are given an array <code>tasks</code> where <code>tasks[i] = [actual<sub>i</sub>, minimum<sub>i</sub>]</code>:</p>\n\n<ul>\n\t<li><code>actual<sub>i</sub></code> is the actual amount of energy you <strong>spend to finish</strong> the <code>i<sup>th</sup></code> task.</li>\n\t<li><code>minimum<sub>i</sub></code> is the minimum amount of energy you <strong>require to begin</strong> the <code>i<sup>th</sup></code> task.</li>\n</ul>\n\n<p>For example, if the task is <code>[10, 12]</code> and your current energy is <code>11</code>, you cannot start this task. However, if your current energy is <code>13</code>, you can complete this task, and your energy will be <code>3</code> after finishing it.</p>\n\n<p>You can finish the tasks in <strong>any order</strong> you like.</p>\n\n<p>Return <em>the <strong>minimum</strong> initial amount of energy you will need</em> <em>to finish all the tasks</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [[1,2],[2,4],[4,8]]\n<strong>Output:</strong> 8\n<strong>Explanation:</strong>\nStarting with 8 energy, we finish the tasks in the following order:\n    - 3rd task. Now energy = 8 - 4 = 4.\n    - 2nd task. Now energy = 4 - 2 = 2.\n    - 1st task. Now energy = 2 - 1 = 1.\nNotice that even though we have leftover energy, starting with 7 energy does not work because we cannot do the 3rd task.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [[1,3],[2,4],[10,11],[10,12],[8,9]]\n<strong>Output:</strong> 32\n<strong>Explanation:</strong>\nStarting with 32 energy, we finish the tasks in the following order:\n    - 1st task. Now energy = 32 - 1 = 31.\n    - 2nd task. Now energy = 31 - 2 = 29.\n    - 3rd task. Now energy = 29 - 10 = 19.\n    - 4th task. Now energy = 19 - 10 = 9.\n    - 5th task. Now energy = 9 - 8 = 1.</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [[1,7],[2,8],[3,9],[4,10],[5,11],[6,12]]\n<strong>Output:</strong> 27\n<strong>Explanation:</strong>\nStarting with 27 energy, we finish the tasks in the following order:\n    - 5th task. Now energy = 27 - 5 = 22.\n    - 2nd task. Now energy = 22 - 2 = 20.\n    - 3rd task. Now energy = 20 - 3 = 17.\n    - 1st task. Now energy = 17 - 1 = 16.\n    - 4th task. Now energy = 16 - 4 = 12.\n    - 6th task. Now energy = 12 - 6 = 6.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= tasks.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= actual<sub>i</sub>&nbsp;&lt;= minimum<sub>i</sub>&nbsp;&lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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