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leetcode-cn/problem (English)/x 的平方根 (English) [sqrtx].html Normal file
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<p>Given a non-negative integer <code>x</code>,&nbsp;compute and return <em>the square root of</em> <code>x</code>.</p>
<p>Since the return type&nbsp;is an integer, the decimal digits are <strong>truncated</strong>, and only <strong>the integer part</strong> of the result&nbsp;is returned.</p>
<p><strong>Note:&nbsp;</strong>You are not allowed to use any built-in exponent function or operator, such as <code>pow(x, 0.5)</code> or&nbsp;<code>x ** 0.5</code>.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> x = 4
<strong>Output:</strong> 2
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> x = 8
<strong>Output:</strong> 2
<strong>Explanation:</strong> The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>0 &lt;= x &lt;= 2<sup>31</sup> - 1</code></li>
</ul>