update

leetcode-cn/problem (English)/LRU 缓存(English) [lru-cache-lcci].html

@@ -0,0 +1,22 @@
+<p>Design and build a &quot;least recently used&quot; cache, which evicts the least recently used item. The cache should map from keys to values (allowing you to insert and retrieve a value associ&shy;ated with a particular key) and be initialized with a max size. When it is full, it should evict the least recently used item.</p>
+
+<p>You should implement following operations:&nbsp;&nbsp;<code>get</code>&nbsp;and <code>put</code>.</p>
+
+<p>Get a value by key:&nbsp;<code>get(key)</code> - If key is in the cache, return the value, otherwise return -1.<br />
+Write a key-value pair to the cache:&nbsp;<code>put(key, value)</code> - If the key is not in the cache, then write its value to the cache. Evict the least recently used item before writing if necessary.</p>
+
+<p><strong>Example:</strong></p>
+
+<pre>
+LRUCache cache = new LRUCache( 2 /* capacity */ );
+
+cache.put(1, 1);
+cache.put(2, 2);
+cache.get(1);       // returns 1
+cache.put(3, 3);    // evicts key 2
+cache.get(2);       // returns -1 (not found)
+cache.put(4, 4);    // evicts key 1
+cache.get(1);       // returns -1 (not found)
+cache.get(3);       // returns 3
+cache.get(4);       // returns 4
+</pre>