coder-xiaomo/leetcode-problemset
1
0
Fork 0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-10-19 03:56:46 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee

update

Browse Source
This commit is contained in:
小墨
2022-03-29 12:43:11 +08:00
parent 58bbdfd57c
commit 2b0511d272
10721 changed files with 8123 additions and 8119 deletions
Download Patch File Download Diff File Expand all files Collapse all files

54
leetcode-cn/problem (Chinese)/K 个一组翻转链表 [reverse-nodes-in-k-group].html Normal file
View File

@@ -0,0 +1,54 @@
<p>给你一个链表，每 <em>k </em>个节点一组进行翻转，请你返回翻转后的链表。</p>
<p><em>k </em>是一个正整数，它的值小于或等于链表的长度。</p>
<p>如果节点总数不是 <em>k </em>的整数倍，那么请将最后剩余的节点保持原有顺序。</p>
<p><strong>进阶：</strong></p>
<ul>
<li>你可以设计一个只使用常数额外空间的算法来解决此问题吗？</li>
<li><strong>你不能只是单纯的改变节点内部的值</strong>，而是需要实际进行节点交换。</li>
</ul>
<p> </p>
<p><strong>示例 1：</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/10/03/reverse_ex1.jpg" style="width: 542px; height: 222px;" />
<pre>
<strong>输入：</strong>head = [1,2,3,4,5], k = 2
<strong>输出：</strong>[2,1,4,3,5]
</pre>
<p><strong>示例 2：</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/10/03/reverse_ex2.jpg" style="width: 542px; height: 222px;" />
<pre>
<strong>输入：</strong>head = [1,2,3,4,5], k = 3
<strong>输出：</strong>[3,2,1,4,5]
</pre>
<p><strong>示例 3：</strong></p>
<pre>
<strong>输入：</strong>head = [1,2,3,4,5], k = 1
<strong>输出：</strong>[1,2,3,4,5]
</pre>
<p><strong>示例 4：</strong></p>
<pre>
<strong>输入：</strong>head = [1], k = 1
<strong>输出：</strong>[1]
</pre>
<ul>
</ul>
<p><strong>提示：</strong></p>
<ul>
<li>列表中节点的数量在范围 <code>sz</code> 内</li>
<li><code>1 <= sz <= 5000</code></li>
<li><code>0 <= Node.val <= 1000</code></li>
<li><code>1 <= k <= sz</code></li>
</ul>