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leetcode-cn/problem (Chinese)/整数反转 [reverse-integer].html Normal file
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<p>给你一个 32 位的有符号整数 <code>x</code> ，返回将 <code>x</code> 中的数字部分反转后的结果。</p>
<p>如果反转后整数超过 32 位的有符号整数的范围 <code>[−2<sup>31</sup>,  2<sup>31 </sup>− 1]</code> ，就返回 0。</p>
<strong>假设环境不允许存储 64 位整数（有符号或无符号）。</strong>
<p> </p>
<p><strong>示例 1：</strong></p>
<pre>
<strong>输入：</strong>x = 123
<strong>输出：</strong>321
</pre>
<p><strong>示例 2：</strong></p>
<pre>
<strong>输入：</strong>x = -123
<strong>输出：</strong>-321
</pre>
<p><strong>示例 3：</strong></p>
<pre>
<strong>输入：</strong>x = 120
<strong>输出：</strong>21
</pre>
<p><strong>示例 4：</strong></p>
<pre>
<strong>输入：</strong>x = 0
<strong>输出：</strong>0
</pre>
<p> </p>
<p><strong>提示：</strong></p>
<ul>
<li><code>-2<sup>31</sup> <= x <= 2<sup>31</sup> - 1</code></li>
</ul>