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<p>给定二叉树的根节点&nbsp;<code>root</code>&nbsp;,返回所有左叶子之和。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2021/04/08/leftsum-tree.jpg" /></p>
<pre>
<strong>输入:</strong> root = [3,9,20,null,null,15,7]
<strong>输出:</strong> 24
<strong>解释:</strong> 在这个二叉树中,有两个左叶子,分别是 9 和 15所以返回 24
</pre>
<p><strong>示例&nbsp;2:</strong></p>
<pre>
<strong>输入:</strong> root = [1]
<strong>输出:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li>节点数在&nbsp;<code>[1, 1000]</code>&nbsp;范围内</li>
<li><code>-1000 &lt;= Node.val &lt;= 1000</code></li>
</ul>
<p>&nbsp;</p>