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leetcode-cn/problem (Chinese)/字符串的最大公因子 [greatest-common-divisor-of-strings].html Normal file
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<p>对于字符串&nbsp;<code>s</code> 和&nbsp;<code>t</code>，只有在&nbsp;<code>s = t + ... + t</code>（<code>t</code> 自身连接 1 次或多次）时，我们才认定&nbsp;“<code>t</code> 能除尽 <code>s</code>”。</p>
<p>给定两个字符串&nbsp;<code>str1</code>&nbsp;和&nbsp;<code>str2</code>&nbsp;。返回 <em>最长字符串&nbsp;<code>x</code>，要求满足&nbsp;<code>x</code> 能除尽 <code>str1</code> 且&nbsp;<code>X</code> 能除尽 <code>str2</code></em> 。</p>
<p>&nbsp;</p>
<p><strong>示例 1：</strong></p>
<pre>
<strong>输入：</strong>str1 = "ABCABC", str2 = "ABC"
<strong>输出：</strong>"ABC"
</pre>
<p><strong>示例 2：</strong></p>
<pre>
<strong>输入：</strong>str1 = "ABABAB", str2 = "ABAB"
<strong>输出：</strong>"AB"
</pre>
<p><strong>示例 3：</strong></p>
<pre>
<strong>输入：</strong>str1 = "LEET", str2 = "CODE"
<strong>输出：</strong>""
</pre>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ul>
<li><code>1 &lt;= str1.length, str2.length &lt;= 1000</code></li>
<li><code>str1</code>&nbsp;和&nbsp;<code>str2</code>&nbsp;由大写英文字母组成</li>
</ul>