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leetcode-cn/problem (Chinese)/和为零的N个唯一整数 [find-n-unique-integers-sum-up-to-zero].html Normal file
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<p>给你一个整数&nbsp;<code>n</code>，请你返回 <strong>任意&nbsp;</strong>一个由 <code>n</code>&nbsp;个 <strong>各不相同&nbsp;</strong>的整数组成的数组，并且这 <code>n</code> 个数相加和为 <code>0</code> 。</p>
<p>&nbsp;</p>
<p><strong>示例 1：</strong></p>
<pre><strong>输入：</strong>n = 5
<strong>输出：</strong>[-7,-1,1,3,4]
<strong>解释：</strong>这些数组也是正确的 [-5,-1,1,2,3]，[-3,-1,2,-2,4]。
</pre>
<p><strong>示例 2：</strong></p>
<pre><strong>输入：</strong>n = 3
<strong>输出：</strong>[-1,0,1]
</pre>
<p><strong>示例 3：</strong></p>
<pre><strong>输入：</strong>n = 1
<strong>输出：</strong>[0]
</pre>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ul>
<li><code>1 &lt;= n &lt;= 1000</code></li>
</ul>