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leetcode-cn/problem (Chinese)/可被 K 整除的最小整数 [smallest-integer-divisible-by-k].html Normal file
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<p>给定正整数 <code>k</code>&nbsp;，你需要找出可以被 <code>k</code>&nbsp;整除的、仅包含数字 <code><strong>1</strong></code> 的最 <strong>小</strong> 正整数 <code>n</code>&nbsp;的长度。</p>
<p>返回 <code>n</code>&nbsp;的长度。如果不存在这样的 <code>n</code>&nbsp;，就返回-1。</p>
<p><strong>注意：</strong> <code>n</code>&nbsp;不符合 64 位带符号整数。</p>
<p>&nbsp;</p>
<p><strong>示例 1：</strong></p>
<pre>
<strong>输入：</strong>k = 1
<strong>输出：</strong>1
<strong>解释：</strong>最小的答案是 n = 1，其长度为 1。</pre>
<p><strong>示例 2：</strong></p>
<pre>
<strong>输入：</strong>k = 2
<strong>输出：</strong>-1
<strong>解释：</strong>不存在可被 2 整除的正整数 n 。</pre>
<p><strong>示例 3：</strong></p>
<pre>
<strong>输入：</strong>k = 3
<strong>输出：</strong>3
<strong>解释：</strong>最小的答案是 n = 111，其长度为 3。</pre>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ul>
<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>
</ul>