coder-xiaomo/leetcode-problemset
1
0
Fork 0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-10-19 12:06:48 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee

update

Browse Source
This commit is contained in:
小墨
2022-03-29 12:43:11 +08:00
parent 58bbdfd57c
commit 2b0511d272
10721 changed files with 8123 additions and 8119 deletions
Download Patch File Download Diff File Expand all files Collapse all files

39
leetcode-cn/problem (Chinese)/分数到小数 [fraction-to-recurring-decimal].html Normal file
View File

@@ -0,0 +1,39 @@
<p>给定两个整数，分别表示分数的分子&nbsp;<code>numerator</code> 和分母 <code>denominator</code>，以 <strong>字符串形式返回小数</strong> 。</p>
<p>如果小数部分为循环小数，则将循环的部分括在括号内。</p>
<p>如果存在多个答案，只需返回 <strong>任意一个</strong> 。</p>
<p>对于所有给定的输入，<strong>保证</strong> 答案字符串的长度小于 <code>10<sup>4</sup></code> 。</p>
<p>&nbsp;</p>
<p><strong>示例 1：</strong></p>
<pre>
<strong>输入：</strong>numerator = 1, denominator = 2
<strong>输出：</strong>"0.5"
</pre>
<p><strong>示例 2：</strong></p>
<pre>
<strong>输入：</strong>numerator = 2, denominator = 1
<strong>输出：</strong>"2"
</pre>
<p><strong>示例 3：</strong></p>
<pre>
<strong>输入：</strong>numerator = 4, denominator = 333
<strong>输出：</strong>"0.(012)"
</pre>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ul>
<li><code>-2<sup>31</sup> &lt;=&nbsp;numerator, denominator &lt;= 2<sup>31</sup> - 1</code></li>
<li><code>denominator != 0</code></li>
</ul>