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leetcode-cn/problem (Chinese)/二叉树的后序遍历 [binary-tree-postorder-traversal].html Normal file
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<p>给你一棵二叉树的根节点 <code>root</code> ，返回其节点值的 <strong>后序遍历 </strong>。</p>
<p>&nbsp;</p>
<p><strong>示例 1：</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/08/28/pre1.jpg" style="width: 127px; height: 200px;" />
<pre>
<strong>输入：</strong>root = [1,null,2,3]
<strong>输出：</strong>[3,2,1]
</pre>
<p><strong>示例 2：</strong></p>
<pre>
<strong>输入：</strong>root = []
<strong>输出：</strong>[]
</pre>
<p><strong>示例 3：</strong></p>
<pre>
<strong>输入：</strong>root = [1]
<strong>输出：</strong>[1]
</pre>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ul>
<li>树中节点的数目在范围 <code>[0, 100]</code> 内</li>
<li><code>-100 &lt;= Node.val &lt;= 100</code></li>
</ul>
<p>&nbsp;</p>
<p><strong>进阶：</strong>递归算法很简单，你可以通过迭代算法完成吗？</p>