update

leetcode-cn/originData/uncrossed-lines.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>在两条独立的水平线上按给定的顺序写下 <code>nums1</code> 和 <code>nums2</code> 中的整数。</p>\n\n<p>现在，可以绘制一些连接两个数字 <code>nums1[i]</code>&nbsp;和 <code>nums2[j]</code>&nbsp;的直线，这些直线需要同时满足满足：</p>\n\n<ul>\n\t<li>&nbsp;<code>nums1[i] == nums2[j]</code></li>\n\t<li>且绘制的直线不与任何其他连线（非水平线）相交。</li>\n</ul>\n\n<p>请注意，连线即使在端点也不能相交：每个数字只能属于一条连线。</p>\n\n<p>以这种方法绘制线条，并返回可以绘制的最大连线数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/04/26/142.png\" style=\"width: 400px; height: 286px;\" />\n<pre>\n<strong>输入：</strong>nums1 = <span id=\"example-input-1-1\">[1,4,2]</span>, nums2 = <span id=\"example-input-1-2\">[1,2,4]</span>\n<strong>输出：</strong><span id=\"example-output-1\">2</span>\n<strong>解释：</strong>可以画出两条不交叉的线，如上图所示。 \n但无法画出第三条不相交的直线，因为从 nums1[1]=4 到 nums2[2]=4 的直线将与从 nums1[2]=2 到 nums2[1]=2 的直线相交。\n</pre>\n\n<div>\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = <span id=\"example-input-2-1\">[2,5,1,2,5]</span>, nums2 = <span id=\"example-input-2-2\">[10,5,2,1,5,2]</span>\n<strong>输出：</strong><span id=\"example-output-2\">3</span>\n</pre>\n\n<div>\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = <span id=\"example-input-3-1\">[1,3,7,1,7,5]</span>, nums2 = <span id=\"example-input-3-2\">[1,9,2,5,1]</span>\n<strong>输出：</strong><span id=\"example-output-3\">2</span></pre>\n\n<p>&nbsp;</p>\n</div>\n</div>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length, nums2.length &lt;= 500</code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[j] &lt;= 2000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n",
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             "difficulty": "Medium",
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@@ -143,7 +143,7 @@
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             "hints": [
                 "Think dynamic programming.  Given an oracle dp(i,j) that tells us how many lines A[i:], B[j:]  [the sequence A[i], A[i+1], ... and B[j], B[j+1], ...] are uncrossed, can we write this as a recursion?"
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