update

leetcode-cn/originData/subarray-product-less-than-k.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给定一个正整数数组 <code>nums</code>和整数 <code>k</code> 。</p>\n\n<p>请找出该数组内乘积小于 <code>k</code> 的连续的子数组的个数。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [10,5,2,6], k = 100\n<strong>输出:</strong> 8\n<strong>解释:</strong> 8个乘积小于100的子数组分别为: [10], [5], [2], [6], [10,5], [5,2], [2,6], [5,2,6]。\n需要注意的是 [10,5,2] 并不是乘积小于100的子数组。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [1,2,3], k = 0\n<strong>输出:</strong> 0</pre>\n\n<p> </p>\n\n<p><strong>提示: </strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 3 * 10<sup>4</sup></code></li>\n\t<li><code>1 <= nums[i] <= 1000</code></li>\n\t<li><code>0 <= k <= 10<sup>6</sup></code></li>\n</ul>\n",
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             "difficulty": "Medium",
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             "hints": [
                 "For each j, let opt(j) be the smallest i so that nums[i] * nums[i+1] * ... * nums[j] is less than k.  opt is an increasing function."
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