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"translatedContent": "<p>给定一个长度为 <code>n</code> 的整数数组 <code>nums</code> 。</p>\n\n<p>假设 <code>arr<sub>k</sub></code> 是数组 <code>nums</code> 顺时针旋转 <code>k</code> 个位置后的数组,我们定义 <code>nums</code> 的 <strong>旋转函数</strong> <code>F</code> 为:</p>\n\n<ul>\n\t<li><code>F(k) = 0 * arr<sub>k</sub>[0] + 1 * arr<sub>k</sub>[1] + ... + (n - 1) * arr<sub>k</sub>[n - 1]</code></li>\n</ul>\n\n<p>返回 <em><code>F(0), F(1), ..., F(n-1)</code>中的最大值 </em>。</p>\n\n<p>生成的测试用例让答案符合 <strong>32 位</strong> 整数。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [4,3,2,6]\n<strong>输出:</strong> 26\n<strong>解释:</strong>\nF(0) = (0 * 4) + (1 * 3) + (2 * 2) + (3 * 6) = 0 + 3 + 4 + 18 = 25\nF(1) = (0 * 6) + (1 * 4) + (2 * 3) + (3 * 2) = 0 + 4 + 6 + 6 = 16\nF(2) = (0 * 2) + (1 * 6) + (2 * 4) + (3 * 3) = 0 + 6 + 8 + 9 = 23\nF(3) = (0 * 3) + (1 * 2) + (2 * 6) + (3 * 4) = 0 + 2 + 12 + 12 = 26\n所以 F(0), F(1), F(2), F(3) 中的最大值是 F(3) = 26 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [100]\n<strong>输出:</strong> 0\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>-100 <= nums[i] <= 100</code></li>\n</ul>\n",
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