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小墨
2022-05-02 23:44:12 +08:00
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leetcode-cn/originData/repeated-string-match.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>给定两个字符串&nbsp;<code>a</code> 和 <code>b</code>，寻找重复叠加字符串 <code>a</code> 的最小次数，使得字符串 <code>b</code> 成为叠加后的字符串 <code>a</code> 的子串，如果不存在则返回 <code>-1</code>。</p>\n\n<p><strong>注意：</strong>字符串 <code>&quot;abc&quot;</code>&nbsp;重复叠加 0 次是 <code>&quot;&quot;</code>，重复叠加 1 次是&nbsp;<code>&quot;abc&quot;</code>，重复叠加 2 次是&nbsp;<code>&quot;abcabc&quot;</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>a = &quot;abcd&quot;, b = &quot;cdabcdab&quot;\n<strong>输出：</strong>3\n<strong>解释：</strong>a 重复叠加三遍后为 &quot;ab<strong>cdabcdab</strong>cd&quot;, 此时 b 是其子串。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>a = &quot;a&quot;, b = &quot;aa&quot;\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>a = &quot;a&quot;, b = &quot;a&quot;\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>a = &quot;abc&quot;, b = &quot;wxyz&quot;\n<strong>输出：</strong>-1\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= a.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= b.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>a</code> 和 <code>b</code> 由小写英文字母组成</li>\n</ul>\n",
"isPaidOnly": false,
"difficulty": "Medium",
"likes": 265,
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"dislikes": 0,
"isLiked": null,
"similarQuestions": "[{\"title\": \"Repeated Substring Pattern\", \"titleSlug\": \"repeated-substring-pattern\", \"difficulty\": \"Easy\", \"translatedTitle\": \"\\u91cd\\u590d\\u7684\\u5b50\\u5b57\\u7b26\\u4e32\"}]",
@@ -143,7 +143,7 @@
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