update

leetcode-cn/originData/range-sum-of-sorted-subarray-sums.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你一个数组&nbsp;<code>nums</code>&nbsp;，它包含&nbsp;<code>n</code>&nbsp;个正整数。你需要计算所有非空连续子数组的和，并将它们按升序排序，得到一个新的包含&nbsp;<code>n * (n + 1) / 2</code>&nbsp;个数字的数组。</p>\n\n<p>请你返回在新数组中下标为<em>&nbsp;</em><code>left</code>&nbsp;到&nbsp;<code>right</code> <strong>（下标从 1 开始）</strong>的所有数字和（包括左右端点）。由于答案可能很大，请你将它对 10^9 + 7 取模后返回。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,4], n = 4, left = 1, right = 5\n<strong>输出：</strong>13 \n<strong>解释：</strong>所有的子数组和为 1, 3, 6, 10, 2, 5, 9, 3, 7, 4 。将它们升序排序后，我们得到新的数组 [1, 2, 3, 3, 4, 5, 6, 7, 9, 10] 。下标从 le = 1 到 ri = 5 的和为 1 + 2 + 3 + 3 + 4 = 13 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,4], n = 4, left = 3, right = 4\n<strong>输出：</strong>6\n<strong>解释：</strong>给定数组与示例 1 一样，所以新数组为 [1, 2, 3, 3, 4, 5, 6, 7, 9, 10] 。下标从 le = 3 到 ri = 4 的和为 3 + 3 = 6 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,4], n = 4, left = 1, right = 10\n<strong>输出：</strong>50\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10^3</code></li>\n\t<li><code>nums.length == n</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 100</code></li>\n\t<li><code>1 &lt;= left &lt;= right&nbsp;&lt;= n * (n + 1) / 2</code></li>\n</ul>\n",
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@@ -155,7 +155,7 @@
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             "hints": [
                 "Compute all sums and save it in array.",
                 "Then just go from LEFT to RIGHT index and calculate answer modulo 1e9 + 7."