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"translatedContent": "<div class=\"original__bRMd\">\n<div>\n<p>有 <code>n</code> 个城市,其中一些彼此相连,另一些没有相连。如果城市 <code>a</code> 与城市 <code>b</code> 直接相连,且城市 <code>b</code> 与城市 <code>c</code> 直接相连,那么城市 <code>a</code> 与城市 <code>c</code> 间接相连。</p>\n\n<p><strong>省份</strong> 是一组直接或间接相连的城市,组内不含其他没有相连的城市。</p>\n\n<p>给你一个 <code>n x n</code> 的矩阵 <code>isConnected</code> ,其中 <code>isConnected[i][j] = 1</code> 表示第 <code>i</code> 个城市和第 <code>j</code> 个城市直接相连,而 <code>isConnected[i][j] = 0</code> 表示二者不直接相连。</p>\n\n<p>返回矩阵中 <strong>省份</strong> 的数量。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/graph1.jpg\" style=\"width: 222px; height: 142px;\" />\n<pre>\n<strong>输入:</strong>isConnected = [[1,1,0],[1,1,0],[0,0,1]]\n<strong>输出:</strong>2\n</pre>\n\n<p><strong>示例 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/graph2.jpg\" style=\"width: 222px; height: 142px;\" />\n<pre>\n<strong>输入:</strong>isConnected = [[1,0,0],[0,1,0],[0,0,1]]\n<strong>输出:</strong>3\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 200</code></li>\n\t<li><code>n == isConnected.length</code></li>\n\t<li><code>n == isConnected[i].length</code></li>\n\t<li><code>isConnected[i][j]</code> 为 <code>1</code> 或 <code>0</code></li>\n\t<li><code>isConnected[i][i] == 1</code></li>\n\t<li><code>isConnected[i][j] == isConnected[j][i]</code></li>\n</ul>\n</div>\n</div>\n",
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