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2022-05-02 23:44:12 +08:00
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leetcode-cn/originData/number-of-boomerangs.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>给定平面上<em>&nbsp;</em><code>n</code><em> </em>对 <strong>互不相同</strong> 的点&nbsp;<code>points</code> ，其中 <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> 。<strong>回旋镖</strong> 是由点&nbsp;<code>(i, j, k)</code> 表示的元组 ，其中&nbsp;<code>i</code>&nbsp;和&nbsp;<code>j</code>&nbsp;之间的距离和&nbsp;<code>i</code>&nbsp;和&nbsp;<code>k</code>&nbsp;之间的欧式距离相等（<strong>需要考虑元组的顺序</strong>）。</p>\n\n<p>返回平面上所有回旋镖的数量。</p>\n&nbsp;\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>points = [[0,0],[1,0],[2,0]]\n<strong>输出：</strong>2\n<strong>解释：</strong>两个回旋镖为 <strong>[[1,0],[0,0],[2,0]]</strong> 和 <strong>[[1,0],[2,0],[0,0]]</strong>\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>points = [[1,1],[2,2],[3,3]]\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>points = [[1,1]]\n<strong>输出：</strong>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n ==&nbsp;points.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 500</code></li>\n\t<li><code>points[i].length == 2</code></li>\n\t<li><code>-10<sup>4</sup> &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= 10<sup>4</sup></code></li>\n\t<li>所有点都 <strong>互不相同</strong></li>\n</ul>\n",
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"difficulty": "Medium",
"likes": 233,
"likes": 236,
"dislikes": 0,
"isLiked": null,
"similarQuestions": "[{\"title\": \"Line Reflection\", \"titleSlug\": \"line-reflection\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u76f4\\u7ebf\\u955c\\u50cf\"}]",
@@ -149,7 +149,7 @@
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