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"translatedContent": "<p>对整数的二进制表示取反(<code>0</code> 变 <code>1</code> ,<code>1</code> 变 <code>0</code>)后,再转换为十进制表示,可以得到这个整数的补数。</p>\n\n<ul>\n\t<li>例如,整数 <code>5</code> 的二进制表示是 <code>\"101\"</code> ,取反后得到 <code>\"010\"</code> ,再转回十进制表示得到补数 <code>2</code> 。</li>\n</ul>\n\n<p>给你一个整数 <code>num</code> ,输出它的补数。</p>\n\n<p> </p>\n\n<ol>\n</ol>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>num = 5\n<strong>输出:</strong>2\n<strong>解释:</strong>5 的二进制表示为 101(没有前导零位),其补数为 010。所以你需要输出 2 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>num = 1\n<strong>输出:</strong>0\n<strong>解释:</strong>1 的二进制表示为 1(没有前导零位),其补数为 0。所以你需要输出 0 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= num < 2<sup>31</sup></code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>注意:</strong>本题与 1009 <a href=\"https://leetcode-cn.com/problems/complement-of-base-10-integer/\">https://leetcode-cn.com/problems/complement-of-base-10-integer/</a> 相同</p>\n",
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