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2022-05-02 23:44:12 +08:00
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leetcode-cn/originData/minimum-number-of-days-to-eat-n-oranges.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>厨房里总共有 <code>n</code>&nbsp;个橘子，你决定每一天选择如下方式之一吃这些橘子：</p>\n\n<ul>\n\t<li>吃掉一个橘子。</li>\n\t<li>如果剩余橘子数 <code>n</code>&nbsp;能被 2 整除，那么你可以吃掉 <code>n/2</code> 个橘子。</li>\n\t<li>如果剩余橘子数&nbsp;<code>n</code>&nbsp;能被 3 整除，那么你可以吃掉 <code>2*(n/3)</code> 个橘子。</li>\n</ul>\n\n<p>每天你只能从以上 3 种方案中选择一种方案。</p>\n\n<p>请你返回吃掉所有 <code>n</code>&nbsp;个橘子的最少天数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>n = 10\n<strong>输出：</strong>4\n<strong>解释：</strong>你总共有 10 个橘子。\n第 1 天：吃 1 个橘子，剩余橘子数 10 - 1 = 9。\n第 2 天：吃 6 个橘子，剩余橘子数 9 - 2*(9/3) = 9 - 6 = 3。（9 可以被 3 整除）\n第 3 天：吃 2 个橘子，剩余橘子数 3 - 2*(3/3) = 3 - 2 = 1。\n第 4 天：吃掉最后 1 个橘子，剩余橘子数 1 - 1 = 0。\n你需要至少 4 天吃掉 10 个橘子。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 6\n<strong>输出：</strong>3\n<strong>解释：</strong>你总共有 6 个橘子。\n第 1 天：吃 3 个橘子，剩余橘子数 6 - 6/2 = 6 - 3 = 3。（6 可以被 2 整除）\n第 2 天：吃 2 个橘子，剩余橘子数 3 - 2*(3/3) = 3 - 2 = 1。（3 可以被 3 整除）\n第 3 天：吃掉剩余 1 个橘子，剩余橘子数 1 - 1 = 0。\n你至少需要 3 天吃掉 6 个橘子。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>n = 1\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>n = 56\n<strong>输出：</strong>6\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2*10^9</code></li>\n</ul>\n",
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"difficulty": "Hard",
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@@ -143,7 +143,7 @@
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"hints": [
"In each step, choose between 2 options:\r\nminOranges = 1 + min( (n%2) + f(n/2), (n%3) + f(n/3) )\r\nwhere f(n) is the minimum number of days to eat n oranges."
],