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"translatedContent": "<p>你打算利用空闲时间来做兼职工作赚些零花钱。</p>\n\n<p>这里有 <code>n</code> 份兼职工作,每份工作预计从 <code>startTime[i]</code> 开始到 <code>endTime[i]</code> 结束,报酬为 <code>profit[i]</code>。</p>\n\n<p>给你一份兼职工作表,包含开始时间 <code>startTime</code>,结束时间 <code>endTime</code> 和预计报酬 <code>profit</code> 三个数组,请你计算并返回可以获得的最大报酬。</p>\n\n<p>注意,时间上出现重叠的 2 份工作不能同时进行。</p>\n\n<p>如果你选择的工作在时间 <code>X</code> 结束,那么你可以立刻进行在时间 <code>X</code> 开始的下一份工作。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/10/19/sample1_1584.png\" style=\"width: 300px;\"></strong></p>\n\n<pre><strong>输入:</strong>startTime = [1,2,3,3], endTime = [3,4,5,6], profit = [50,10,40,70]\n<strong>输出:</strong>120\n<strong>解释:\n</strong>我们选出第 1 份和第 4 份工作, \n时间范围是 [1-3]+[3-6],共获得报酬 120 = 50 + 70。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/10/19/sample22_1584.png\" style=\"height: 112px; width: 600px;\"> </strong></p>\n\n<pre><strong>输入:</strong>startTime = [1,2,3,4,6], endTime = [3,5,10,6,9], profit = [20,20,100,70,60]\n<strong>输出:</strong>150\n<strong>解释:\n</strong>我们选择第 1,4,5 份工作。 \n共获得报酬 150 = 20 + 70 + 60。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/10/19/sample3_1584.png\" style=\"height: 112px; width: 400px;\"></strong></p>\n\n<pre><strong>输入:</strong>startTime = [1,1,1], endTime = [2,3,4], profit = [5,6,4]\n<strong>输出:</strong>6\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= startTime.length == endTime.length == profit.length <= 5 * 10^4</code></li>\n\t<li><code>1 <= startTime[i] < endTime[i] <= 10^9</code></li>\n\t<li><code>1 <= profit[i] <= 10^4</code></li>\n</ul>\n",
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"difficulty": "Hard",
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@@ -155,7 +155,7 @@
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"hints": [
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"Think on DP.",
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"Sort the elements by starting time, then define the dp[i] as the maximum profit taking elements from the suffix starting at i.",
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