update

leetcode-cn/originData/maximum-product-of-word-lengths.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你一个字符串数组&nbsp;<code>words</code> ，找出并返回 <code>length(words[i]) * length(words[j])</code>&nbsp;的最大值，并且这两个单词不含有公共字母。如果不存在这样的两个单词，返回 <code>0</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = <code>[\"abcw\",\"baz\",\"foo\",\"bar\",\"xtfn\",\"abcdef\"]</code>\n<strong>输出：</strong><code>16 \n<strong>解释</strong></code><strong>：</strong><code>这两个单词为<strong> </strong>\"abcw\", \"xtfn\"</code>。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = <code>[\"a\",\"ab\",\"abc\",\"d\",\"cd\",\"bcd\",\"abcd\"]</code>\n<strong>输出：</strong><code>4 \n<strong>解释</strong></code><strong>：</strong>这两个单词为 <code>\"ab\", \"cd\"</code>。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = <code>[\"a\",\"aa\",\"aaa\",\"aaaa\"]</code>\n<strong>输出：</strong><code>0 \n<strong>解释</strong></code><strong>：</strong><code>不存在这样的两个单词。</code>\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= words.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 1000</code></li>\n\t<li><code>words[i]</code>&nbsp;仅包含小写字母</li>\n</ul>\n",
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